<u>Answer:</u> The mass of solution that the chemistry student should use is 23.4 grams
<u>Explanation:</u>
We are given:
Available mass of isopropenylbenzene = 120. g
Amount of isopropenylbenzene needed by chemistry student = 10.00 g
42.7 % (w/w) solution of isopropenylbenzene.
This means that 42.7 grams of isopropenylbenzene is present in 100 grams of solution.
To calculate the mass of solution for given needed of isopropenylbenzene, we apply unitary method:
For 42.7 grams of isopropenylbenzene, the amount of solution needed is 100 grams
So, for 10.00 grams of isopropenylbenzene, the amount of solution needed will be = 
Hence, the mass of solution that the chemistry student should use is 23.4 grams
The balanced equation would be (1)BaCl2 + (1)H2SO4 --> (1)BaSO4 + (2)HCl2
Then you should know that the coefficients stand for moles.
The thing is I'm not sure if H2SO4 is 35 ml or .200 m.
Also, is this topic stoichiometry?
A single replacement or displacement reaction occurs when one ingredient in a compound replaces another. Only another metal can replace a less active one; a metal can only displace another metal, and a non-metal can only displace another non-metal.
<h3>Displacement reaction:</h3>
The tendency of the element to lose electrons is what makes it metallic. Due to their bigger sizes and propensity to lose electrons as size, the number of shells, and nuclear force of attraction rise, the most active metals are found on the left side of the periodic table.
The reaction in which the more reactive element displaces the less reactive element is known as the displacement reaction.
When we combine an active metal with HCl, the reaction is as follows:
We are taking sodium, Na which is the most active metal. It will replace H in HCl because it is more reactive than H.
2Na + 2HCl → 2NaCl + H₂
Three ways to recognize if a single displacement reaction has taken place:
1. Color change
2. Formation of bubbles (a gas)
3. Formation of a precipitate
Learn more about displacement reaction here:
brainly.com/question/15343606
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