Answer:
A: T = 120 N
B: T = 88.42 N
C: T = 70 N
Explanation:
Part A:
Since, the lighter bucket is supported by my had. So, the only unbalanced force in the system is the weight of heavier bucket. Hence, the tension in rope will be equal to the weight of heavier bucket.
<u>T = 120 N</u>
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Part B:
This is the case where, two masses hang vertically on both sides of the pulley. To find the tension in such case we have the formula:
T = (2 m₁m₂g)/(m₁+m₂)
where,
m₁ = mass of heavier object = W₁/g = (120 N)/(9.8 m/s²) = 12.24 kg
m₁ = mass of lighter object = W₂/g = (70 N)/(9.8 m/s²) = 7.14 kg
g = 9.8 m/s²
Therefore,
T = [(2)(12.24 kg)(7.14 kg)(9.8 m/s²)]/(12.24kg + 7.14 kg)
T = 1713.6 N.kg/19.38 kg
<u>T = 88.42 N</u>
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Part C:
Since, the heavier bucket is on ground. So, its weight is balanced by the normal reaction of the ground. The only unbalanced force in the system is the weight of lighter bucket. Hence, the tension in rope will be equal to the weight of lighter bucket.
<u>T = 70 N</u>
Answer:
x =4.5 10⁴ m
Explanation:
To find the distance that the particle moves we must use the equations of motion in one dimension and to find the acceleration of the particle we will use Newton's second law
m = 2.00 mg (1 g / 1000 ug) (1 Kg / 1000g) = 2.00 10-6 Kg
q = -200 nc (1C / 10 9 nC) = -200 10-9 C
Let's calculate the acceleration
F = ma
F = q E
a = qE / m
a = -200 10⁻⁹ 1000 / 2.00 10⁻⁶
a = 1 10² m / s²
Let's use kinematics to find the distance traveled before stopping, where it has zero speed (Vf = 0)
Vf² = Vo² -2 a x
0 = Vo² - 2 a x
x = Vo² / 2a
x = 3000²/ 2100
x =4.5 10⁴ m
This is the distance the particule stop, after this distance in the field accelerates in the opposite direction of the initial
Second part
In this case Newton's second law is applied on the y axis
F -W = 0
F = w = mg
E q = mg
E = mg / q
E = 2.00 10⁻⁶ 9.8 / 200 10⁻⁹
E = 9.8 10⁵ C
The direction of the field is such that the force on the particle is up, as the particle has a negative charge, the field must be directed downwards F = qE = (-q) E
Physics is explicitly involved in studying <span>the motion of a spacecraft under gravitational influence. Thus the answer is C.
Physic focuses more on the measurement, gravity, distances, acceleration and motion. THough all the choices are sciences but the C. is the topic that physics is involved.</span>
An object that orbits another object in space is called a satellite.
Hope that helped =)