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mel-nik [20]
3 years ago
13

Kirchoff's Law states that, by the time current has returned to its source, all

Engineering
2 answers:
Alchen [17]3 years ago
6 0

Kirchoff's law  states that by the time current has reached to its source all voltage must be used.

<u>Explanation:</u>

Kirchoff's voltage law states that the algebraic sum of all the voltages across a closed loop is zero. As the circuit is a closed conducting path, no energy is lost.  ices All the voltage that is supplied from the voltage source is dropped at the devices in the circuit.

The potential difference maintained by the voltage source enables the flow of current across the circuit. As the supplied voltage drops at each elements of the circuit, all voltage is used by the time current has returned to the surface.

Alex17521 [72]3 years ago
4 0

Kirchoff's Law Kirchoff's Law states that, by the time current has returned to its source is explained in the following.

Explanation:

  • Kirchhoff's Current Law (KCL) is Kirchhoff's first law that deals with the conservation of charge entering and leaving a junction. ... In other words the algebraic sum of ALL the currents entering and leaving a junction must be equal to zero.
  • Kirchoff's laws apply for a given instant in time. So the voltages at a given moment around a loop will all sum to zero, or currents in a node sum to zero if you look at the instantaneous voltage and current. But they will be out of phase.
  • Kirchhoff Voltage Law states that ''The algebraic sum of all voltages (source voltage and voltage drops) is equal to zero around a close path''. This is called KVL ( Kirchhoff Voltage Law) equation. The source voltage is equal to the sum of all voltage drops.
  • Kirchhoff's Voltage Law (KVL) is Kirchhoff's second law that deals with the conservation of energy around a closed circuit path.
  • Kirchhoff's laws can be used to determine the values of unknown values like current, Voltage in the circuit. These laws can be applied on any circuit (with some limitation), and useful to find the unknown values in complex circuits and networks.

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mixas84 [53]

Answer:

work done = 48.88 × 10^{9} J

Explanation:

given data

mass = 100 kN

velocity =  310 m/s

time = 30 min = 1800 s

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to find out

work done by the shuttle engine

solution

we know that work done here is

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work done = ( mass ×velocity ×time  - force ×velocity ×time  - mass ×descends )  10³ J

work done = ( 100 × 310 × 1800  - 12×310 ×1800  - 100 × 2200 )  10³ J

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3 years ago
Consider a multiprocessor system and a multithreaded program written using the many-to-many threading model. Let the number of u
Montano1993 [528]

Answer:

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Answer:

Option A

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Answer:

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