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3 years ago

The production of carbon dioxide might be an indicator of what process

Physics

2 answers:

disa [49]3 years ago

6 0

Its a proces of combustion "burning"humans produce carbon dioxide,rocks<plants whatever is burning energy

aalyn [17]3 years ago

3 0

The carbon dioxide is produced by two methods naturally, which is either photosynthesis or by decomposition. The indicator thus for the carbon dioxide production be the decomposition most likely.

<u>Explanation:</u>

The carbon dioxide is produced by the process of decomposition and photosynthesis both. But in the process of photosynthesis it is released as a by product which then consumed in the process of respiration. Therefore if there is ample production, it indicated of decomposition. The decomposition is the decaying process of organic matter.

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Which of the below statements are true?

andrezito [222]

Answer:

Explanation:

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if you start at point A, then go to point B, and back to point A, the displacement is zero because you started and ended at the same point.

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3 years ago

How do the four fundamental forces differ?

Basile [38]

Look at the first person’s answer. Cause I know I’m wrong

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3 years ago

A piece of aluminum has a volume of 1.50 10-3 m3. the coefficient of volume expansion for aluminum is β = 69 ✕ 10-6 (°c)-1. the

Alex17521 [72]

Answer:

W = 3.12 J

Explanation:

Given the volume is 1.50*10^-3 m^3 and the coefficient of volume for aluminum is β = 69*10^-6 (°C)^-1. The temperature rises from 22°C to 320°C. The difference in temperature is 320 - 22 = 298°C, so ΔT = 298°C. To reiterate our known values we have:

β = 69*10^-6 (°C)^-1 V = 1.50*10^-3 m^3 ΔT = 298°C

So we can plug into the thermal expansion equation to find ΔV which is how much the volume expanded (I'll use d instead of Δ because of format):

$dV = \beta V_{0} dT\\dV = (69*10^{-6})( C)^{-1} * (1.50*10^{-3})m^{3} * (298)C\\dV = 3.0843*10^-5$

So ΔV = 3.0843*10^-5 m^3

Now we have ΔV, next we have to solve for the work done by thermal expansion. The air pressure is 1.01 * 10^5 Pa

To get work, multiply the air pressure and the volume change.

$W = P * dV = (1.01 * 10^5)Pa * (3.0843*10^{-5})m^3\\W = 3.115143J$

W = 3.12 J

Hope this helps!

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3 years ago

Robert has just bought a new model roket, and is trying to measure its flight characteristics. The rocket engine package claims

rewona [7]

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4 years ago

Projectile motion is a combination of which two types of motion?

belka [17]

Vertical Free Fall and Constant Horizontal Motion

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3 years ago

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