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Oduvanchick [21]
3 years ago
10

2. How many grams of N2 are required to produce 10.0 grams of NH3? N2 + 3 H2 - 2 NH3

Chemistry
1 answer:
SOVA2 [1]3 years ago
6 0

8.24g

Explanation:

Given parameters;

Mass of NH₃ = 10g

Unknown:

Mass of N₂ = ?

Solution:

  Reaction equation:

               N₂    +    3H₂     →      2NH₃

Step 1: Convert 10.0 g of NH₃ into moles of NH₃

number of moles = \frac{mass}{molar mass}

   molar mass of NH₃ = 14 + 3(1) = 17g/mol

 Number of moles = \frac{10}{17}  = 0.59mole

Step 2: Convert the moles of NH₃ calculated in Step 1 into moles of N₂

       1 mole of N₂    produced 2 mole of NH₃

   

0.59 moles of ammonia would be formed by \frac{0.59}{2} mole = 0.29mole of N₂

Step 3: Convert the moles of N₂ calculated in Step 2 into grams of N₂.

Mass of N₂ = number of moles x molar mass

  Molar mass of N₂ = 14 x 2 = 28g/mol

  Mass of N₂ = 0.29 x 28 = 8.24g

learn more:

Number of moles brainly.com/question/1841136

#learnwithBrainly

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Airida [17]

Answer:

The answer to your question is 3.75 mg

Explanation:

Data

Radium-223

half-life = 11 days

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total time = 44 days

Process

1.- Draw a chart to start the calculation

                Mass           Number of days      Half-lives

                60 mg                    0                           0

                30 mg                    11                            1

                 15 mg                    11                            2

                7.5 mg                    11                           3

               3.75 mg                   11                           4

        Total number of days   44

       Mass active after 44 days = 3.75 mg                                      

           

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3 years ago
(110.3 g) + (45.27 g) + (54.43 g)
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Explanation:

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According to above equation, 1 mol of NaOH reacts with 1 mol of 1 mol of HCl.

So, excess number of moles of HCl present = number of NaOH added for back titration = \frac{0.0980}{1000}\times 23.60 moles = 0.00231 moles

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