Answer:
139.514 metres
Explanation:
Initial velocity of the truck = 6.6 m/s
Acceleration of the truck = 2.8 m/s^2
Time interval = 7.9 s
Therefore we use the formula,
s = ut + 1/2 at^2
*where s(the distance travelled)...u(the initial velocity)...t(the time period)
; s = 6.6(7.9) + 1/2 (2.8)(7.9)^2
; s = 52.14 + 87.374
The distance moved by the truck = 139.514m
Answer:
B convection MERRY CHRISTMAS
Explanation:
Answer:
1. the voltage will be 2.35×12.5 = 29.4V
2. the resistance would be 9.0/6.2= 1.45ohms
3. in series they will add up thus 4+8+12= 24ohms
4. in parallel it will be 2.18ohms
Answer:
wave number = 0.3348 * 10⁻⁸ cm⁻¹
Explanation:
Given data:
K = 4.808 * 10^2 N/m
<u>Determine the wave number for the infrared absorption</u>
considering vibrational Spectre
k' = 2n / λ ---- ( 1 )
λ = c / v ----- ( 2 )
v = √k / u --- ( 3 )
where : k' = wave number, λ = wavelength, c = velocity of light, v = frequency, k = force constant, u = reduced mass
u = 1.90415 for D35Cl
Input equations 2 and 3 into equation 1 to get the final equation
K' = 2n/c * √k / u
= ( 2 * 3.14 ) / 2.98 * 10^8 ] * (√ 4.808 * 10^2 / 1.90415 )
= 33.486 * 10⁻⁸ m⁻¹ ≈ 0.3348 * 10⁻⁸ cm⁻¹
Answer:
75 N
Explanation:
In this problem, the position of the crate at time t is given by

The velocity of the crate vs time is given by the derivative of the position, so it is:

Similarly, the acceleration of the crate vs time is given by the derivative of the velocity, so it is:
[m/s^2]
According to Newton's second law of motion, the force acting on the crate is equal to the product between mass and acceleration, so:

where
m = 5.00 kg is the mass of the crate
At t = 4.10 s, the acceleration of the crate is

And therefore, the force on the crate is:
