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andrew-mc [135]
3 years ago
14

What is the electron configuration of Zn2+

Chemistry
1 answer:
boyakko [2]3 years ago
3 0
. 1s2 2s2 2p6 3s2 3p6 3d10 One point is earned for the correct configuration.
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If atoms are made up smaller parts such as electrons, why are atoms considered the basic unit of matter
julsineya [31]
They are considered the basic units of matter because all mass is made of atoms.
4 0
3 years ago
Someone please help me
ehidna [41]
I hop this will help u

8 0
3 years ago
Element X reacts with chlorine to form an ionic compound that has the formula XCl₂. To which group on the Periodic Table could e
marishachu [46]

Answer:

<u>Group 2 is the correct answer.</u>

Explanation:

<u>Chlorine has a charge -1. It means that X is +2 so that the formula is XCl2. </u>

4 0
3 years ago
What expression approximates the volume of O2 consumed, measure at STP, when 55 g of Al reacts completely with excess O2?2 Al(s)
nikdorinn [45]

Answer : The volume of O_2 consumed are, 0.75\times 2\times 22.4 L.

Explanation :

The balanced chemical reaction will be:

4Al(s)+3O_2(g)\rightarrow 2Al_2O_3(s)

First we have to calculate the moles of Al.

\text{Moles of }Al=\frac{\text{Mass of }Al}{\text{Molar mass of }Al}

Molar mass of Al = 27 g/mole

\text{Moles of }Al=\frac{55g}{27g/mol}=2mole

Now we have to calculate the moles of O_2.

From the reaction we conclude that,

As, 4 mole of Al react with 3 moles of O_2

So, 2 mole of Al react with \frac{3}{4}\times 2=0.75\times 2 moles of O_2

Now we have to calculate the volume of O_2 consumed.

As we know that, 1 mole of substance occupies 22.4 liter volume of gas.

As, 1 mole of O_2 occupies 22.4 liter volume of O_2 gas

So, 0.75\times 2 mole of O_2 occupies 0.75\times 2\times 22.4 liter volume of O_2 gas

Therefore, the volume of O_2 consumed are, 0.75\times 2\times 22.4 L.

3 0
3 years ago
The molarity of concentrated acetic acid is 17.45 M. When acetic acid is diluted in water it is commonly called vinegar with a m
Sladkaya [172]

M1 = 17.45 M

M2 = 0.83 M

V2 = 250 ml

M1. V1= M2. V2

V1 = (M2. V2)/M1 = (0.83× 250)/ 17.45= 11.89 ml

7 0
3 years ago
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