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netineya [11]
4 years ago
13

Suppose the demand for Digital Video Recorders (DVRs) is given by Q = 250 - .25 p + 4 pc, where Q is the quantity of DVRs demand

ed (in 1000s), p is the price of a DVR, and pc is the price of cable television. How much of a change in p must occur for Q to increase by one?
Physics
1 answer:
Alja [10]4 years ago
4 0

Answer:

Δp = -4 units

Explanation:

For calculating how the quantity of DVRs demanded changes, when the price is modified in one unit, we calculate the derivative of Q with respect to p

Q = 250 - 0.25p + 4pc

\frac{dQ}{dp} = -0.25

This means that when the price increases in one unit the quantity of DVRr demanded reduces in 0.25 units. Then the price must be reduced in 4 units for to obtain one unit more demanded.

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Ivan

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6 0
3 years ago
Read 2 more answers
a 230 kg roller coaster reaches the top of the steepest hill with a speed of 6.2 km/h. It then descends the hill, which is at an
igor_vitrenko [27]

Answer: 81.619 kJ

Explanation:

Given

Mass of roller coaster is m=230\ kg

It reaches the steepest hill with speed of u=6.2\ km/h\ or \ 1.72\ m/s

Hill to bottom is 51 m long with inclination of 45^{\circ}

Height of the hill is h=51\sin 45^{\circ}=36.06\ m

Conserving energy to get kinetic energy at bottom

Energy at top=Energy at bottom

\Rightarrow K_t+U_t=K_b+U_b\\\Rightarrow \dfrac{1}{2}mu^2+mgh=K_b+0\\\\\Rightarrow K_b=0.5\times 230\times 1.72^2+230\times 9.8\times 36.06\\\Rightarrow K_b=340.216+81,279.24\\\Rightarrow K_b=81,619.456\ J\\\Rightarrow K_b=81.619\ kJ

8 0
3 years ago
evaluate the force of a skateboard exerts on you if your mass is 60kg and you push on the skateboard with a force of 60N
Sav [38]
Every action has an equal or opposite reaction.
You weigh 60kg 
<span>So your acceleration is 6N / 60 kg = 0.1m/s^2</span>
6 0
3 years ago
Acceleration is often measured in what unit? A. newtons B. kilograms C. meters per second D. meters per second squared
spayn [35]

D. meters per second squared

3 0
4 years ago
Read 2 more answers
An RV is traveling 60 km/h along a highway. A boy sitting near the driver of the RV throws a ball to another boy at the back end
alina1380 [7]

Answer:

Speed of the ball relative to the boys: 25 km/h

Speed of the ball relative to a stationary observer: 35 km/h

Explanation:

The RV is travelling at a velocity of

v_{RV}=+60 km/h

Here we have taken the direction of motion of the RV as positive direction.

The boy sitting near the driver throws the ball back with speed of 25 km/h, so the velocity of the ball in the reference frame of the RV is

v_B = -25 km/h

with negative sign since it is travelling in the opposite direction relative to the RV. Therefore, this is the velocity measured by every observer in the reference frame of the RV: so the speed measured by the boys is

v = 25 km/h

Instead, a stationary observer outside the RV measures a velocity of the ball given by the algebraic sum of the two velocities:

v = +60 km/h + (-25 km/h) = +35 km/h

So, he/she measures a speed of 35 km/h.

5 0
3 years ago
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