The answer is C: "<span>A body cell has 46 chromosomes; a sex cell has 23"</span>
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- zinc [Zn] + copper sulfate [Cu(SO4<span>)
</span>Balanced equation:Zn + Cu(SO4) → Zn(SO4<span>) + Cu
- </span>aluminum [Al] + copper sulfate[Cu(SO4)]Balanced equation:2Al + 3Cu(SO4) → Al2(SO4)3<span>+ 3Cu
- </span>zinc [Zn] + silver nitrate [Ag(NO3)]Balanced equation:Zn + 2Ag(NO3) → 2Ag + Zn(NO3)<span>2
- </span>copper [Cu] + silver nitrate [Ag(NO3)]
Balanced equation:Cu + Ag(NO3) → Cu(NO3<span>) + Ag</span>
Answer : The 
for this reaction is, -88780 J/mole.
Solution :
The balanced cell reaction will be,
Here, magnesium (Cu) undergoes oxidation by loss of electrons, thus act as anode. silver (Ag) undergoes reduction by gain of electrons and thus act as cathode.
The half oxidation-reduction reaction will be :
Oxidation : 
Reduction : 
Now we have to calculate the Gibbs free energy.
Formula used :
where,
= Gibbs free energy = ?
n = number of electrons to balance the reaction = 2
F = Faraday constant = 96500 C/mole
= standard e.m.f of cell = 0.46 V
Now put all the given values in this formula, we get the Gibbs free energy.
Therefore, the for this reaction is, -88780 J/mole.
The answer is: when the aim is to show electron distributions in shells
An orbital notation is more appropriate if you want to show how the electrons of an atom are distributed in each subshell. This is because there are some atoms that have special electronic configurations that aren't obvious in just written configurations.
