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DiKsa [7]
3 years ago
10

How many moles of H2O will be produced from 26.0 g of H2022 Stoichiome

Chemistry
1 answer:
lukranit [14]3 years ago
5 0

Answer:

                       0.7644 moles of H₂O

Explanation:

                    The balance chemical equation is as follow;

                                      2 H₂O₂ → 2 H₂O + O₂

To solve this problem we will first calculate the moles of H₂O₂ as,

                           Moles  =  Mass / M/Mass

                           Moles  =  26.0 g / 34.01 g/mol

                           Moles  =  0.7644 mol

Secondly,

According to equation,

                      2 moles of H₂O₂ produces  =  2 moles of H₂O

Hence,

                0.7644 mol of H₂O₂ will produce  =  X moles of H₂O

Solving for X,

                        X  =  2 mol × 0.7644 mol / 2 mol

                       X =  0.7644 moles of H₂O

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Please help me
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Answer:

pH = 6.999

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Explanation:

HBr is a strong acid, a very strong one.

In water, this acid is totally dissociated.

HBr + H₂O  →  H₃O⁺  +  Br⁻

We can think pH, as - log 7.75×10⁻¹² but this is 11.1

acid pH can't never be higher than 7.

We apply the charge balance:

[H⁺] = [Br⁻] + [OH⁻]

All the protons come from the bromide and the OH⁻ that come from water.

We can also think [OH⁻] = Kw / [H⁺] so:

[H⁺] = [Br⁻] + Kw / [H⁺]

Now, our unknown is [H⁺]

[H⁺] =  7.75×10⁻¹² + 1×10⁻¹⁴ / [H⁺]

[H⁺] = (7.75×10⁻¹² [H⁺] + 1×10⁻¹⁴) /  [H⁺]

This is quadratic equation:  [H⁺]² - 7.75×10⁻¹² [H⁺] - 1×10⁻¹⁴

a = 1 ; b = - 7.75×10⁻¹² ; c = -1×10⁻¹⁴

(-b +- √(b² - 4ac) / (2a)

[H⁺] = 1.000038751×10⁻⁷

- log [H⁺] = pH → 6.999

A very strong acid as HBr, in this case, it is so diluted that its pH is almost neutral.

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