I think the answer is : Bobby exactly three years old today
to put it simply, absolute time can be perceived without depended to other object as comparison.
for example Evan is older than james is not an absolute time, because this conditions depend on the age comparison between the two subject
Answer:
Vy = 0
y(max) = 137,76 m
x(max) = 318 m
Explanation:
We are dealing with a projectile movement
And from problem statement we know:
θ = 60⁰ then sin θ = sin 60⁰ = √3/2 and cos 60⁰ = 1/2 and g = 9.8 m/sec²
V₀ = 60 m/sec
V₀x = V₀ *cosθ Vx = V₀x Vx = Constant then Vx = V₀ *cosθ
Then Vx = 60* 1/2 Vx = 30 m/sec
V₀y = V₀ *sinθ ⇒ V₀y =60*√3/2 ⇒ V₀y = = 30*√3 m/sec
Vy = V₀y * sin θ - g*t
When Vy = 0 (maximum height point) we are half of the way for the ball to hit the ground, then
Vy = 0 ⇒ V₀y - g*t = 0 ⇒ 30*√3 (m /sec) = 9,8 (m/sec²)* t
t = 30*√3/9.8 t = 5.30 sec
y(max) = y₀ + V₀y*t - 1/2 * g*t²
By substitution:
y (max) = 0 + 30*√3 * 5.30 - 0,5* 9.8* (5.3)²
y(max) = 275,40 - 137,64
y(max) = 137,76 m
And finally x(max)
x(max) = Vx *t = 30* 2*5,3
x(max) = 318 m
False i’m not too sure but hope i helped<3
Time = distance/speed, as you surely know. About the scientific notation, you just need to express the result as a number with one digit and the rest in decimal places with 10^... I can't see the exponents in your question and it's late here. Good luck! For instance, 6.434*10^3 ... I recall it takes about 5 hours, so you should get there, so about 5 * 3600 = 18000 seconds. Nice!
The best way to find that you want is the line fit. When acceleration is constant the speed(v) changes smoothly every moment, so the v line must be straight. Differently, the accelaration changes.