Answer:
34.45m
Explanation:
Using the equation of motion formula v² = u²+2as to get the distance travelled
v is the final velocity = 26m/s
u is the initial velocity = 0m/s
a is the acceleration due to gravity = 9.81m/s²
S is the distance travelled
Substituting the given values into the formula;
26² = 0²+2(9.81)s
676 = 0 + 19.62s
19.62s = 676
s = 676/19.62
s = 34.45m
Hence the distance she would travel during the race is 34.45m
Answer:
The runner's average acceleration is 0.102 m/s²
Explanation:
The runner accelerates from 5 m/s to 5.2 m/s and covering 10 m
We need to find the runner's average acceleration
The given is:
→ Initial velocity 5 m/s
→ Final velocity 5.2 m/s
→ Distance 10 meters
→ Acceleration ?
We need a suitable rule for the given
→ v² = u² + 2 a s
where v is the final velocity, u is the initial velocity, a is the acceleration
and s is the distance
Substitute the values above in the rule
→ (5.2)² = (5)² + 2 a (10)
→ 27.04 = 25 + 20 a
Subtract 25 from both sides
→2.04 = 20 a
Divide both sides by 20
→ a = 0.102 m/s²
<em>The runner's average acceleration is 0.102 m/s²</em>
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