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Rainbow [258]
4 years ago
11

How the atomic radius (the size) of elements changes as we go down?

Chemistry
2 answers:
katrin [286]4 years ago
8 0
Radius of atoms increase as you go down, can decrease from left to right in certain periods
Brums [2.3K]4 years ago
7 0
The further down from the group (top to bottom) the atomic radius increases, while the energy level (left to right) decreases
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Which statement describes a reason to consider air a mixture? A) The major constituents of air are gaseous elements. B) The comp
umka21 [38]

The correct answer is - A) The major constituents of air are gaseous elements.

With the statement ''the major constituents of air are gaseous elements'' we can easily conclude that the air is a mixture. The reason for that is that we have a plural usage of the word element, elements, which mean that there are multiple elements that make up the air.

The air is indeed predominantly a mixture of gaseous elements. The most abundant gas in the air being the nitrogen with 78.9%, oxygen with 20.95%, argon 0.93%, and carbon dioxide 0.04%, with lesser amounts of other gases also be present in it. The water vapor is also present in the air, though it is variable, being around 1% at sea level, but only 0.4% over the entire atmosphere.

3 0
4 years ago
What is the molar mass of sulfur (S)?
Lesechka [4]

Answer:

A. 32.06 g/mol

Explanation:

The molar mass units are always g/mol

8 0
3 years ago
Read 2 more answers
HELPPPPP PLEASE!!!
Salsk061 [2.6K]
C I think it’s C I’m semi guessing
5 0
3 years ago
Write the balanced chemical equation for the reaction between aqueous sodium carbonate and
ioda

Answer:

2HNO3 (aq) + Na2CO3 (aq) → 2NaNO3 (aq) + CO2 (g) + H2O (l)

Explanation:

This question is asking to write and balance an equation between between aqueous sodium carbonate (Na2CO3) and aqueous nitric acid (HNO3). The equation is as follows:

HNO3 (aq) + Na2CO3 (aq) → NaNO3 (aq) + CO2 (g) + H2O (l)

However, this equation is not balanced as the number of atoms of each element must be the same on both sides of the equation. To balance the equation, one will make use of coefficients as follows:

2HNO3 (aq) + Na2CO3 (aq) → 2NaNO3 (aq) + CO2 (g) + H2O (l)

7 0
3 years ago
A 40.5 g sample of aluminum is cooled 7.5°C. The specific heat capacity of aluminum is
sweet-ann [11.9K]
Q=mc\Delta T
Q= 40.5g x 0.900 J/g degree Celsius x 7.5
Q= 273.4 J.
Even if it is cooled , we use the same temperature as heating it.
3 0
3 years ago
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