Question

How does hooke's law explain the behavior of elastic materials?

Answer 1

Fs = -k*(change in x)

This equation relates the force exerted on a spring to the distance it compresses to it's individual 'spring constant' or basically its level of springiness for lack of a better term. This help?

Answer 2

Answer:

Explanation:

Hooke's law establishes the relationship between elongation or longitudinal stretching and applied force. Elasticity is the physical property in which objects capable of changing shape when a deformation force acts on an object. In other words, this law affirms that the elastic deformation suffered by a body is proportional to the force produced by such deformation, as long as the elasticity limit is not exceeded.

Mathematically, Hooke's law states that the applied force F is equal to a constant k multiplied by the displacement or change in length x:

F = k * x

or F= k*(x-x₀)

where:

• F is the modulus of force that is applied to the spring.
• k is the elastic spring constant, which relates force and elongation. It depends on the pier.
• x₀ is the length of the spring without applying force.
• x is the length of the spring with the force applied.

The force is expressed in Newtons (N) and the elongation of the body in meters (m). Therefore, the units used to express Hooke's law are in Newtons / Meters.

In this way, the displacement or deformation suffered by an object subjected to a force will be directly proportional to the deforming force or the load. That is, at greater force, greater deformation or displacement.