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kupik [55]
3 years ago
15

Which of these substances, when dissolved in water, is a strong electrolyte? which of these substances, when dissolved in water,

is a strong electrolyte? sucrose folic acid sodium nitrate ammonia hydrofluoric acid?
Chemistry
1 answer:
Norma-Jean [14]3 years ago
5 0
<span>Option C. It is sodium nitrate because it is a strong electrolyte that comes from a strong acid (HNO3) and a strong base (KOH). It becomes a strong electrolyte when it dissolves in water, its formula is NaNO3, which is a compound that forms nitrate together with potassium nitrate and is obtained by chemical synthesis.</span>
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Calculate the mass of 29.8 mL of aluminum, which has a density of 2.00 g/mL.
MaRussiya [10]

Answer:

The answer is

<h2>59.6 g </h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

Density of aluminum = 2.00 g/mL

volume = 29.8 mL

The mass is

mass = 2 × 29.8

We have the final answer as

<h3>59.6 g</h3>

Hope this helps you

5 0
3 years ago
A 104 m3 thoroughly mixed pond has a water inflow and outflow of 5 m3/h. The inflow water contains 0.01 mol/m3 of chemical. Chem
Naily [24]

Answer:

C ≈ 1.44 × 10⁻³ mol/m³

Explanation:

The given information are;

The liquid volume the pond can hold = 104 m³

The volume of inflow into the pond = 5 m³/h

The volume of outflow into the pond = 5 m³/h

The concentration of the chemical in the inflow water = 0.01 mol/m³

The concentration of the chemical discharged directly into the water = 0.1 mol/h

The concentration, c_{(inflow)}, of chemical that enters the water through inflow per hour is given as follows;

c_{(inflow)} = 0.01 mol/m³ × 5 m³/h = 0.05 mol/h

The concentration, c_{(discharge)}, of chemical that enters the water through direct discharge per hour is given as follows;

c_{(discharge)} = 0.1 mol/h

The total concentration that enters the pond per hour is given as follows;

c_{(inflow)} + c_{(discharge)} = 0.1 mol/h + 0.05 mol/h = 0.15 mol/h

Whereby the water in the pond properly mixes with the pond, we have;

The concentration of chemicals (C) in the outflow water = 0.15 mol/(104 m³) ≈ 0.00144 mol/m³

C ≈ 1.44 × 10⁻³ mol/m³.

4 0
3 years ago
Liquid hexane e (CH 3 (CH 2 ) 4 CH 3 ) will react with gaseous oxygen (O 2 ) to produce gaseous carbon dioxide (CO 2 ) and gaseo
soldi70 [24.7K]

Answer:

Explanation:

Hi I'm so sorry hope you have a good day

7 0
3 years ago
With what compound will nh3 experience only dispersion intermolecular forces? with what compound will nh3 experience only disper
Burka [1]
Answer is: ammonia experience only dispersion intermolecular forces with BF₃ (boron trifluoride) because BF₃ is only nonpolar molecule (vectors of dipole moments cansel each other, dipole moment is zero).
The London dispersion force (intermolecular force) <span>is a temporary attractive </span>force between molecules.
6 0
3 years ago
Read 2 more answers
How much energy is evolved during the formation of 197 g of Fe, according to the reaction below?
hoa [83]

Answer:

ΔH for formation of 197g Fe⁰ = 1.503 x 10³ Kj => Answer choice 'B'

Explanation:

Given Fe₂O₃(s) + 2Al⁰(s) => Al₂O₃(s) + 2Fe⁰(s) + 852Kj

197g Fe⁰ = (197g/55.85g/mol) = 3.527 mol Fe⁰(s)

From balanced standard equation 2 moles Fe⁰(s) => 852Kj, then ...

3.527 mole yield (a higher mole value) => (3.527/2) x 852Kj = 1,503Kj (a higher enthalpy value).

______

NOTE => If 2 moles Fe gives 852Kj (exo) as specified in equation, then a <u>higher energy value</u> would result if the moles of Fe⁰(s) is <u>higher than 2 moles</u>. The ratio of 3.638/2 will increase the listed equation heat value to a larger number because 197g Fe⁰(s) contains more than 2 moles of Fe⁰(s) => 3.527 mole Fe(s) in 197g.  Had the problem asked for the heat loss from <u>less than two moles Fe⁰(s)</u> - say 100g Fe⁰(s) (=1.79mole Fe⁰(s)) - then one would use the fractional ratio (1.79/2) to reduce the enthalpy value less than 852Kj.  

8 0
3 years ago
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