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disa [49]
3 years ago
7

Physics lenses/critical angle question need help ASAP

Physics
1 answer:
zavuch27 [327]3 years ago
8 0

The answer should be B.

There are 2 conditions for total internal reflection:

  • Light travels from an optically denser medium to an optically less dense medium.
  • Angle of incidence (the angle between the incident ray and the normal) is greater than the critical angle.

For this question, light is travelling from glass to air, so the first condition is fulfilled. Yet, the angle of incidence is only 30°, which is less than the critical angle. Therefore, total internal reflection will not occur.

Instead, there will be refraction. Light ray bends away from normal when it is travelling to a less dense object, thus having a greater angle of refraction than the angle of incidence.

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Help quick (edge 2021)
kow [346]

Answer:

a

Explanation:

8 0
3 years ago
1. During the Middle Ages, armies often attacked castles using large siege engines such as the counterweight trebuchet at left.
fredd [130]

Answer: Some challenges that I could see would be the walls, possibly a moat, tar, and the towers.

Explanation: The wall is obliviously a main problem, trying to get over it or through it is a difficult challenge. The moat (if it has one) means that there is more than likely only one way to get in or out.  If it does have tar it means that the attackers are going to be put in a "sticky situation" And finally the towers, they have people at the top shooting arrows down at you, or throwing things at you.

8 0
3 years ago
what is the mass of vertical column of air that exerts pressure of 1 atm over a10m by 10m square surface
Oksana_A [137]

Answer:

m=1.01\times 10^6\ kg

Explanation:

Given that,

Pressure, P = 1 atm = 101325 Pa

Area of the square surface, A = 10² = 100 m²

We need to find the mass of vertical column of air. We know that, pressure is equal to the force acting per unit area. So,

P=\dfrac{mg}{A}\\\\m=\dfrac{PA}{g}\\\\m=\dfrac{101325\times 10^2}{10}\\\\m=1.01\times 10^6\ kg

So, the required mass of the vertical column of air is 1.01\times 10^6\ kg.

4 0
3 years ago
A 1.0-kg ball is attached to the end of a 2.5-m string to form a pendulum. This pendulum is released from rest with the string h
hram777 [196]

Answer:

v_{2}=3.5 m/s

Explanation:

Using the conservation of energy we have:

\frac{1}{2}mv^{2}=mgh

Let's solve it for v:

v=\sqrt{2gh}

So the speed at the lowest point is v=7 m/s

Now, using the conservation of momentum we have:

m_{1}v_{1}=m_{2}v_{2}

v_{2}=\frac{1*7}{2}

Therefore the speed of the block after the collision is v_{2}=3.5 m/s

I hope it helps you!

       

8 0
3 years ago
An electron is emmited by an atomic nucleus in the process of...
Sliva [168]
I’m pretty sure it’s Radioactive decay
8 0
3 years ago
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