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disa [49]
2 years ago
7

Physics lenses/critical angle question need help ASAP

Physics
1 answer:
zavuch27 [327]2 years ago
8 0

The answer should be B.

There are 2 conditions for total internal reflection:

  • Light travels from an optically denser medium to an optically less dense medium.
  • Angle of incidence (the angle between the incident ray and the normal) is greater than the critical angle.

For this question, light is travelling from glass to air, so the first condition is fulfilled. Yet, the angle of incidence is only 30°, which is less than the critical angle. Therefore, total internal reflection will not occur.

Instead, there will be refraction. Light ray bends away from normal when it is travelling to a less dense object, thus having a greater angle of refraction than the angle of incidence.

You might be interested in
A student throws a rock upwards. The rock reaches a maximum height 2.4 seconds after it was released.
Allisa [31]

Answer:

23.52 m/s

Explanation:

The following data were obtained from the question:

Time taken (t) to reach the maximum height = 2.4 s

Acceleration due to gravity (g) = 9.8 m/s²

Initial velocity (u) =..?

At the maximum height, the final velocity (v) is zero. Thus, we can obtain how fast the rock (i.e initial velocity)

was thrown as follow:

v = u – gt (since the rock is going against gravity)

0 = u – (9.8 × 2.4)

0 = u – 23.52

Collect like terms

0 + 23.52 = u

u = 23.52 m/s

Therefore, the rock was thrown at a velocity of 23.52 m/s.

7 0
3 years ago
A flying squirrel has a mass of 0. 765 kg. He jumps off the tree and hits the ground with 125 joules of energy. Determine how hi
uranmaximum [27]

Answer:

Height, h = 16.67 m

Explanation:

We have,

Mass of a squirrel is 0.765 kg.

He jumps off the tree and hits the ground with 125 joules of energy.

It is required to find the height up on the tree the squirrel was when it jumped.

The energy possessed by the squirrel is called its gravitational potential energy. It can be given by :

E=mgh

h is height up on the tree the squirrel was when it jumped

h=\dfrac{E}{mg}\\\\h=\dfrac{125\ J}{0.765\ kg\times 9.8\ m/s^2}\\\\h=16.67\ m

So, the squirrel will go to a height of 16.67 m.

6 0
3 years ago
Fter carrying out some tests at a local stream, you discover that the pH in the stream is extremely low. Based on this, you shou
n200080 [17]

Answer:

D) not swim in or drink the water from the stream

Explanation:

Low pH means the water is acidic which is harmful to your skin as it can cause burns and irritations. So any means of contacting with water is not healthy. The damage to the skin happens as in acidic water it has more H+ than in the neutral water and the extra H+ ions can ionize the atoms  which are combined to form different compounds in the skin when in contact.

5 0
3 years ago
Read 2 more answers
Peyote contains a psychotropic drug called __________.
Fiesta28 [93]

Answer:

B. Mescaline

Explanation:

4 0
3 years ago
You place a chunk of naturally radioactive (it means not enriched for nuclear purposes) material on the not very exact scale and
Ber [7]

Answer:

he mass of the emitted particles is small, it is slightly less than the initial 50 kg, so the correct answer is the first.

Explanation:

A radioactive material is transformed into another material by the emission of some particular radioactive ones, the most common being alpha and beta rays, which is why in the transformation process a certain amount of mass is lost. The process is described by the expression

             

              N = No e^{- \alpha /t}

 

From this expression the quantity half life time (T_{1/2}) is defined with time so that half of the atoms have been transformed

           

            T_{1/2} = ln 2 /λ

in this case it does not indicate that T_{1/2}= 20 days is worth, for which periods have passed, in the first the number of radioactive atoms was reduced to half the number, leaving N´ and the second halved the number of nuclei that they were radioactive, leaving radioactive nuclei

first time of life

              N´ = ½ N

second time of life

              N´´ = ½ N´

              N´´ = ¼ N

consequently in the sample at the end of these two decay periods we have, assuming that after each emission the atom is stable (non-radioactive). After the first emission there are n₁ = N / 2 stable atoms, after the second emission n₂ = ¼ N stable atoms are added and there are still n₃ = ¼ N radioactive atoms, so the total number of atoms is

 

             n_total = n₁ + n₂ + n₃

Recall that the mass of the initial radioactive atoms is m₁, when transforming its mass of stable atoms is m₂ where

            m₂ < m₁

therefore mass of

 

             m_total = m₂ N / 2 + m₂ N / 4 + m₁ N / 4

             m_total = m₂ ¾ N + m₁ ¼ N

             m_total = N (  ¾ m₂ + ¼ m₁)

Since the mass of the emitted particles is small, it is slightly less than the initial 50 kg, so the correct answer is the first.

8 0
2 years ago
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