Ptotal=Ptotal —> m1v1+m2v2=m1v1’+m2v2’ —> (1kg)(2m/s)+(1kg)(0m/s)=(1kg)(-1m/s)+(1kg)(v2’) —> v2’=3m/s
answer: v=3m/s
Answer:
I did this essay before, its not hard. Just read through it carefully and you'll figure it out. or just ask you mom, dad, guardian, or teacher for help
A). No. The entire poster is already covered with atoms,
but they're too small to see.
B). No. What's "life-size" of an atom ? It's too small to see,
and that's the whole problem.
D). No. Atoms are too small to see even with a microscope.
C). Yes ! A model of an atom, big enough to see, would help
get <em><u>some</u></em> of the important ideas across.
Answer:
The speed of the stone when it is 4.66 m higher is 236.057 m/s.
Explanation:
Given the initial velocity and vertical distance, we can use the fourth kinematic equation (
) to find v final, or the v to the left of the equal sign. We know 
(initial velocity) is 24.7 m/s, y (change in vertical distance) is 4.66 m, and a is another way to write g (acceleration due to gravity), or 9.8 
.
From here you could plug in the values and solve for v final, but to make the solving process simpler, we can simplify the given equation, <em>then </em>plug in the known values.
To isolate v final, we can take the square root of 
and do the same to the right side of the equation. Therefore, we can find v final with: 
, where v initial is outside of the square root because it squared...
If we plug in the known values to the simplified equation, we get: 
The final answer is 236.057 m/s.
