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enyata [817]
4 years ago
7

Aluminum is a highly reactive metal that oxidizes when exposed to air. Which of these would be a good first step in balancing th

is reaction? Al + O2 → Al2O3 A) Put a coefficient of 3 on Al B) Put a coefficient of 3 on O2 C) Put a coefficient of 2 on O2 D) Put a coefficient of 3 on Al2O3
Physics
2 answers:
Mila [183]4 years ago
8 0
The answer is B. because when u add 3 on O2 and multiplied together makes 6

Helga [31]4 years ago
8 0

Answer: B) Put a coefficient of 3 on O_2

Explanation: According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The balancing starts with the maximum number of atoms and thus first oxygen needs to get balanced by putting a coefficient of 3 on reactant side.

The balanced chemical equation will be:

4Al+3O_2\rightarrow 2Al_2O_3

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A copper wire has a square cross section 2.0 mm on a side. The wire is 5.0 m long and carries a current of 2.0 A. The density of
kondor19780726 [428]

Answer:

30.22 hours

Explanation:

Given data:

A= l² = (2 x 10^{-3})² = 4 x 10^{-6} m²

Length 'L' = 5m

current 'I' = 2 A

density of free electrons 'n'= 8.5 x 10^{28} /m³

Current Density 'J' = I/ A

J= 2/4 x 10^{-6}

J= 5 x 10^{5} A/m²

We can determine the  time required for an electron to travel the length of the wire by

T= L/ Vd

Where,

L is length and Vd is drift velocity.

Vd can be defined by J/ n|q|

where,

n is the charge-carrier number density

|q| is is the charge carried by each charge carrier =>1.6 x 10^{-19}C

T= L/ Vd

Therefore,

T= L . n|q| / J

T= (4 x 8.5 x 10^{28} x |1.6 x 10^{-19}|)/5 x 10^{5}

T= 108800 seconds =>1813.33 minutes

Converting minute into hours:

T= 30.22 hours

Thus, time that is required for an electron to travel the length of the wire is 30.22 hours

4 0
3 years ago
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