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Shalnov [3]
3 years ago
10

Consider the generic chemical equation below. X + Ymc021-1.jpg W + Z Reactant X contains 199.3 J of chemical energy. Reactant Y

contains 272.3 J of chemical energy. Product W contains 41.9 J of chemical energy. If the reaction loses 111.6 J of chemical energy as it proceeds, how much chemical energy must product Z contain?
Chemistry
1 answer:
natima [27]3 years ago
3 0

The reaction is:

X + Y → W + Z

Chemical energy of reactant X = 199.3 J = Ux

Chemical energy of reactant Y = 272.3 J = Uy

Chemical energy of Product W = 41.9 J = Uw

Chemical energy of Product Z = ? = Uz

Where reaction loses energy = 111.6 J = ΔU

By using the equation:

(Ux + Uy) – (Uw + Uz) = ΔU

Ux + Uy – Uw – Uz = ΔU

Uz = Ux + Uy – Uw –ΔU

Uz = 199.3 + 272.3 – 41.9 – 111.6

Uz = 318.1 J

Product Z must contain 318.1 J chemical energy.

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Calculate the number of Na ions and Cl ions and total number of ions in 14.5g of NaCl.​
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Answer:

Number of Na ions in 14.5 g of NaCl is 1.49 × 10²³.

Number of Cl ions in 14.5 g of NaCl is 1.49 × 10²³.

Total number of ions =  1.49 × 10²³  +  1.49 × 10²³ = 2.98 × 10²³.

Explanation:

1 mole of any compound contains 6.023 × 10²³ molecules.

molecular weight of NaCl is 23 + 35.5 = 58.5 g.

so, 58.5 grams of NaCl makes 1 mole

⇒ 14.5 g of NaCl = \frac{14.5}{58.5} =  0.248 moles.

⇒ 0.248 mole contains 0.248 × 6.023×10²³ molecules

=  1.49 × 10²³ molecules.

And 1 molecule contains 1 Na ion and 1 Cl ion.

⇒ number of Na ions in 14.5 g of NaCl is 1.49 × 10²³.

⇒ number of Cl ions in 14.5 g of NaCl is 1.49 × 10²³.

Total number of ions =  1.49 × 10²³  +  1.49 × 10²³ = 2.98 × 10²³.

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