Answer:
The real risk-free rate is 2.1%
Explanation:
Typically, the return on investment is denoted by the below formula:
return on investment=real risk-free rate+inflation premium+default risk premium+liquidity premium+maturity premium
return on investment is 4.4%
inflation premium is 1.9%
maturity risk premium is 0.4%
liquidity premium is 0%
default risk is also assumed to zero as the treasury bond is backed by the government whose level of default is zero
real risk-free rate=return on investment-inflation premium-default risk-liquidity premium-maturity premium
real risk-free rate=4.4%-1.9%-0%-0%-0.4%
real risk-free rate=2.1%
Explanation:
M₂ = Fr²/GM₁
M₂ = [(132N)(.243m)²]/[(6.67*10^-11N*m²/kg)(1.175*10^4kg)]
M₂ = (7.79N*m²)/(7.84*10^-7N*m²)
M₂ = 9.94*10^6 kg
Answer:
The bubble gum experiment demonstrates the law of conservation of mass in that even though the bubble gum has lost mass, this loss in mass is not because some matter present in the gum has been destroyed, but it has changed form and has been removed from the gum.
Explanation:
In this science experiment, students investigate whether or not chewing gum should be considered eating. During the process of chewing the gum, the gum loses mass. The experiment is used to demonstrate the law of conservation of mass which states that matter can neither be created nor destroyed but may change from one form to another.
The loss in mass of the gum is due to the fact that the sugar present in the gum has changed form and has been removed from the gum. During the process of chewing the gum, the sugar in solid form present in the gum is dissolved in the saliva found in the mouth. The dissolved sugar is then swallowed and passes into the digestive tract for digestion. This shows that even though the bubble gum has lost mass, this loss in mass is not because some matter present in the gum has been destroyed, but it has changed form and has been removed from the gum, This demonstrates the law of conservation of mass.
Answer:
the transmission axis of polarizing sheet makes an angle of
with the horizontal
Explanation:
We have given that intensity of light incident on the sheet 
Average intensity of light emerging from a polarizing sheet 
We have to find the angle between transmission axis with the horizontal
Intensity of light polarizing from sheet is equal to 
So 



So the transmission axis of polarizing sheet makes an angle of
with the horizontal