Ask question

Ask question

All categories

2 years ago

10

As a delivery truck travels along a level stretch of road with constant speed, most of the power developed by the engine is used

to compensate for the energy transformations due to friction forces exerted on the delivery truck by the air and the road. If the power developed by the engine is 5.15 hp, calculate the total friction force acting on the delivery truck (in N) when it is moving at a speed of 30 m/s. One horsepower equals 746 W.

1 answer:

velikii [3]2 years ago

8 0

Answer:

128 N

Explanation:

Power can be defined as

$P = F\cdot v$

<em>F</em> is the force and <em>v</em> is the velocity.

$F = \dfrac{P}{v}$

According to the question, <em>P</em> = 5.15 hp = 5.15 × 746 W.

<em>v</em> = 30 m/s

$F = \dfrac{5.15\times 746\text{ W}}{30\text{ m/s}} = 128 \text{ N}$

Since most of the power is used to compensate for the energy transformations due to friction forces, the total frictional is 128 N

You might be interested in

A particle moving along the y-axis has the potential energy u =4y3j, where y is in m. what is the y-component of the force on th

Ivenika [448]

Potential energy is given as

$U = 4y^3$

now as we know that force is related by potential energy by the formula

$F = - \frac{dU}{dy}$

So it is gradient of energy with position in Y

$F = - \fracd(4y^3}{dy}$

$F = -12y^2 \hat j$

Now at y = 0

$F = 0 N$

at y = 1

$F = - 12*1^2$

$F = - 12 N$

at y = 2

$F = - 12*2^2$

$F = - 48 N$

so above is the forces at given positions

7 0

2 years ago

Check the attached image for the question~

zheka24 [161]

Answer:

put the full thin g

Explanation:

3 0

2 years ago

Z. A force that gives a 8-kg objet an acceleration of 1.6 m/s^2 would give a 2-kg object an

Paladinen [302]

Answer:

$\boxed {\boxed {\sf D.\ 6.4\ m/s^2}}$

Explanation:

We need to find the acceleration of the 2 kilogram object. Let's complete this in 2 steps.

<h3>1. Force of 1st Object </h3>

First, we can find the force of the first, 8 kilogram object.

According to Newton's Second Law of Motion, force is the product of mass and acceleration.

$F=m \times a$

The mass of the object is 8 kilograms and the acceleration is 1.6 meters per square second.

m= 8 kg
a= 1.6 m/s²

Substitute these values into the formula.

$F= 8 \ kg * 1.6 \ m/s^2$

Multiply.

$F= 12.8 \ kg*m/s^2$

<h3>2. Acceleration of the 2nd Object </h3>

Now, use the force we just calculated to complete the second part of the problem. We use the same formula:

$F= m \times a$

This time, we know the force is 12.8 kilograms meters per square second and the mass is 2 kilograms.

F= 12.8 kg *m/s²
m= 2 kg

Substitute the values into the formula.

$12.8 \ kg*m/s^2= 2 \ kg *a$

Since we are solving for the acceleration, we must isolate the variable (a). It is being multiplied by 2 kg. The inverse of multiplication is division. Divide both sides of the equation by 2 kg.

$\frac {12.8 \ kg*m/s^2}{2 \ kg}= \frac{2\ kg* a}{2 \ kg}$

$\frac {12.8 \ kg*m/s^2}{2 \ kg}=a$

The units of kilograms cancel.

$\frac {12.8}{2}\ m/s^2=a$

$6.4 \ m/s^2=a$

The acceleration is 6.4 meters per square second.

4 0

2 years ago

Elaborate on the classification of aluminum. A) Aluminum is a noble gas and has a full valence electron shell, is chemically non

scZoUnD [109]

The correct option is (B) <span>Aluminum is a metal and is shiny, malleable, ductile, conducts heat and electricity, forms basic oxides, and forms cations in aqueous solution.

Since Aluminium is in group 13, and all the elements in group 13 are either metals or metalloids(Boron). Hence we are left with option (B) and (D). Boron is the only metalloid in group 13 and aluminium is a metal(not a metalloid); therefore, we are left with only one option which is Option (B). And Aluminium is </span>shiny, malleable, ductile, conducts heat and electricity, forms basic oxides, and forms cations in aqueous solution.<span>
</span><span>
</span>

4 0

2 years ago

Read 2 more answers

The mini-refrigerator fire was most likely caused by what type of wiring?

Nimfa-mama [501]

Answer: The copper wiring most likely caused the mini-refrigerator fire.

Explanation: A mini-refrigerator may have one or more evaporator fan motors. These motors have copper wiring. In some situation these copper wires gets overheated. It may result to the firing of the mini-refrigerator.

Therefore, the mini-refrigerator fire was most likely caused by copper wiring.

7 0

3 years ago