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faust18 [17]
3 years ago
14

Which is a source of AC current?

Physics
1 answer:
Serjik [45]3 years ago
4 0

Which is a source of AC current?

A) Generator

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The charge an electron has spinning around a nucleus.<br><br>(What is it?) <br><br>​
Evgen [1.6K]

Answer:

Negative charge

Explanation:

Electron is an negative charge that spins around the nucleus.

4 0
4 years ago
Read 2 more answers
Which if, any, of these statements are true? (More than one may be true.) Assume the batteries are ideal. Check all that apply.
Maurinko [17]

Answer:

All are true except the last point that says that a battery is a current source and the current at the outlet is always the same.

Explanation:

  • A battery is an electro-chemical device which converts the chemical energy into usable electrical energy thus it provides electrical energy.
  • Since, the battery maintains a a constant potential difference between its terminals, once connected.
  • Since, the movement of electric current requires energy, which is supplied by the electric potential energy stored in the battery.
  • The current in the battery flows as per the Ohm's law and we can not say that the current leaving will always remain constant.
  • As the current is the flow of electric charge, and charges are not stored in batteries unlike capacitors, thus the current at the leaving end will depend on Ohm's law and will vary accordingly.

3 0
3 years ago
A Ferris wheel with a 15-m radius makes three complete revolutions in one minute about its horizontal axis. What is the magnitud
Kay [80]

Answer:

1.48 m/s^2, upward

Explanation:

The passenger on the wheel experiences a centripetal acceleration, which is the one that keeps him in a circular motion.

The direction of this acceleration is always towards the centre of the circular trajectory: so when the passenger is at the lowest point of the ride, the acceleration is upward.

Concerning the magnitude, it is given by

a=\omega^2 r

where

\omega is the angular velocity

r = 15 m is the radius

We need to find the angular velocity; we know that the wheel completes 3 revolutions in one minute. Each revolution corresponds to an angle of 2\pi rad, so the total angular displacement is

\theta = 3 \cdot 2\pi = 6\pi rad

And the time is

t = 1 min = 60 s

So the angular velocity is

\omega = \frac{6\pi}{60 s}=0.314 rad/s

And substituting into the equation of the acceleration,

a=(0.314)^2(15)=1.48 m/s^2

4 0
3 years ago
How can an object become charged
morpeh [17]

Answer:

An object gets charged when it's atoms lose or gain an electron to become an ion. For example: ... This means that the fur loses it's electrons to the plastic rod and both objects are now charged. The fur is positively charged because it lost electrons and the rod is negatively charged because it gained electrons

Explanation:

comment how it helps

3 0
3 years ago
Read 2 more answers
Three ideal polarizing filters are stacked, with the polarizing axis of the second and third filters at 29.0and 58.0, respective
Kryger [21]

Answer:

     I₂ = 143.79

Explanation:

To solve this problem, work them in two parts. A first one where we look for the intensity of the incident light in the set and a second one where we silence the light transmuted by the other set,

Let's start with the set of three curling irons

Beautiful light falls on the first polarized is not polarized, therefore only half the radiation passes

              I₁ = I₀ / 2

this light reaches the second polarized and must comply with the Mule law

             I₂ = I₁ cos² tea

The angle between the first polarized and the second is Tea = 29.0º

             I₂ = I / 2 cos² 29

The light that comes out of the third polarized is

              I₃ = I₂ cos² tea

the angle between the third - second polarizer is

             tea = 58-29

             tea = 29th

               I3 = (I₀ / 2 cos² 29) cos² 29

indicate the output intensity

                I3 = 110

we clear

              I₀ = 2I3 / cos4 29

              I₀ = 2 110 / cos4 29

              I₀ = 375.96 W / cm²

Now we have the incident intensity in the new set of three polarizers

back to the for the first polarizer

                 I₁ = I₀ / 2

when passing the second polarizer

                     I₂ = I1 cos² 29

                    I2 = IO /2 cos²29

let's calculate

                I₂ = 375.96 / 2 cos² 29

               I₂ = 143.79

4 0
4 years ago
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