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dezoksy [38]
3 years ago
15

A 1.0kg ball has a momentum of 12kg m/s what is the balls speed

Physics
1 answer:
Anastasy [175]3 years ago
8 0
The momentum of an object is given by:
p=mv
where
p is the momentum
m is the mass
v is the velocity of the object

The ball in our problem has a mass of m=1.0 kg and a momentum of p=12 kg m/s, therefore we can use the previous formula to find its velocity:
v= \frac{p}{m}= \frac{12 kg m/s}{1.0 kg}=12 m/s
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A large plate carries a uniform charge density σ = 8. 85 × 10-9 c/m2. a pattern showing equipotential surfaces with a 5 v potent
vfiekz [6]

The potential difference comes out to be

10 \times 10 {}^{ - 3} m

Given:

σ = 8. 85 × 10-9 c/m2

we know,

E = \frac{σ}{2ε0}

E =  \frac{8.85 \times 10 {}^{ - 9} }{2ε0}

E =  \frac{v}{d}

given the potential difference between two equipotential surface=5v

E=∆v

∆d=∆v/E

=  \frac{5 \times 8.85 \times 10 { }^{ - 12} \times 2 }{8.85 \times 10 {}^{ - 9} }

Δ = 10 \times 10 {}^{ - 3} m

Thus the potential difference is

10 \times 10 {}^{ - 3} m

Learn more about potential difference from here: brainly.com/question/28165869

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1 year ago
What happens at the end of silence of the lambs?
sukhopar [10]
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borishaifa [10]

Answer:

v = 1 m/s

Explanation:

from the principle of conservation of momentum, we have following relation

initial momentum = final momentum

m_{1}v_{1}+m_{2}v_{2} = (m_{1}+m_{2})v^{2}

where

m1 = 1.14 kg

v1 = 2.0 m/s

m2 = 1.14 kg

v2  = 0 m/s

putting all value in the above equation

1.14 *2.0+ 0 =(1.14+1.14)v^{2}

v =\frac{1.14*2.0}{1.14+1.14}

v = 1 m/s

4 0
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aivan3 [116]

Answer:

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Explanation:

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When two adjacent lights blink on and off in quick succession, we perceive a single light moving back and forth between them. th
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This is called the Phi Phenomenon.
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