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3 years ago

A 1.0kg ball has a momentum of 12kg m/s what is the balls speed

1 answer:

8 0

The momentum of an object is given by:
$p=mv$
where
p is the momentum
m is the mass
v is the velocity of the object

The ball in our problem has a mass of m=1.0 kg and a momentum of $p=12 kg m/s$ , therefore we can use the previous formula to find its velocity:
$v= \frac{p}{m}= \frac{12 kg m/s}{1.0 kg}=12 m/s$

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3 years ago

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3 years ago

An electron has a velocity of 1.50 km/s (in the positive x direction) and an acceleration of 2.00 ✕ 1012 m/s2 (in the positive z

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Answer:

see explanation

Explanation:

Given that,

velocity of 1.50 km/s = 1.50 × 10³m/s

acceleration of 2.00 ✕ 1012 m/s2

electric field has a magnitude of strength of 18.0 N/C

$\bar F= q[\bar E + \bar V \times \bar B]\\\\\bar F = [\bar E + \bar V \times ( B_x \hat i +B_y \hat j +B_z \hat z )]\\\\\\m \bar a = [\bar E + \bar V \times ( B_x \hat i +B_y \hat j +B_z \hat z )]$

$9.1 \times 10^-^3^1 \times 2\times 10^1^2 \hat k=-1.6\times10^-^1^9 \hat k [18\hat k+ 1.5\times 10^3 \hat i \times (B_x \hat i +B_y \hat j +B_z \hat k)]$ $42.2 \times 10^-^1^9 \hat k = -2.4 \times 10^1^6B_y \hat k + 2.4 \times 10 ^1^6 \hat j B_z\\$

$B_x = undetermined$

$B_y = \frac{42.2 \times 10^-^1^9}{-2.4 \times 10^-^1^6} \\\\= - 0.0176 T$

$B_z = 0T$

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4 years ago