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Alchen [17]
3 years ago
8

Once an object enters orbit, what keeps the object moving sideways?

Physics
2 answers:
Makovka662 [10]3 years ago
8 0

Answer:

The right answer is inertia.

Explanation:

This name is given to the tendency of an object that is moving to remain that way, or if it is resting remain that way until an external force act upon it. Basically it means an object does what they are doing unless a force changes their speed or direction.  

yaroslaw [1]3 years ago
7 0

It's the natural tendency of things to keep going unless there's something trying to stop them.

It's usually called "inertia".

Don't get the idea from all of this that things stop unless there's something to keep them going.  The truth is exactly the opposite:  Things keep going unless there's something to make them stop.

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A box weighing 18 N requires a force of 6.0 N to drag it at a constant rate. What is the coefficient of sliding friction?
Rzqust [24]
0.33 . Equation is Force of friction equals normal force times coefficient of friction, so 6=18u. Divide 6 by 18
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Joe walked 1200m East and then turned and walked 600m West. Which statement is true about Joe’s walk
Slav-nsk [51]

Answer:

Velocity is 1m/s

Explanation:

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Kinetic vs potential energy
antiseptic1488 [7]

Answer:

Kinetic energy is the energy obtained from movement while potential energy is the energy in something when it is at a height or has been manipulated in some way; it has work done to it.

Explanation:

Kinetic energy is, like I said, energy gained through movement or action. When an object stops moving, it converts into a different type of energy. Energy cannot be destroyed or created. An object with potential energy has a reference. A reference determines how high it is. The higher and heavier an object is, the more potential energy it has.

Hope this helps!

5 0
2 years ago
When is a body said to be at rest
Dmitry_Shevchenko [17]

rest is the state of a body which is stationary relative to a particular frame of reference or another object.  When the state of a body does not changes with time with respect to its surroundings in a particular frame of reference that time  it is said to be at rest.

in other words we can say that when a body has zero velocity and its position is not changing with time relative to its surrounding then it is said to be at rest.

For example a chair on which you are sitting is at rest or a table on which your desktop is kept is rest because its position is not changing.

3 0
3 years ago
A glider moves along an air track with constant acceleration a. It is projected from the start of the track (x = 0 m) with an in
Pie

Answer:

vo = 0.175m/s

a = -0.040625 m/s^2

Explanation:

To solve this problem, you will need to use the equations for constant acceleration motion:

x = \frac{1}{2}at^2 +v_ot+x_o \\v_f^2 - v_o^2 = 2(x-x_o)a

In the first equation you relate final position with the time elapsed, in the second one, you relate final velocity at any given position. In both equations, you will have both the acceleration a and the initial velocity vo as variables. We can simplify with the information we have:

1. x = \frac{1}{2}at^2 +v_ot+x_o\\0.1m = \frac{1}{2}a(8s)^2 +v_o(8s)+0m \\0.1 = 32a + 8v_o

2. v_f^2 - v_o^2 = 2(x-x_o)a\\(-0.15m/s)^2 - v_o^2 = 2(0.1m-0m)a\\0.0225 - v_o^2 = 0.2a\\a = \frac{0.0225 - v_o^2}{0.2} = 0.1125 - 5v_o^2

Replacing in the first equation:

0.1 = 32(0.1125 - 5v_o^2) + 8v_o\\0.1 = 3.6 - 160v_o^2 + 8v_o\\160v_o^2 - 8v_o - 3.5 = 0

v_0 = \frac{-(-8) +- \sqrt{(-8)^2 - 4(160)(-3.5)}}{2(160)} \\ v_o = 0.175 m/s | -0.125 m/s

But as you are told that the ball was projected om the air track, it only makes sense for the velocity to be positive, otherwise it would have started moving outside the air track, so the real solution is 0.175m/s. Then, the acceleration would be:

a = 0.1125 - 5v_o^2\\a = -0.040625  m/s^2

3 0
3 years ago
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