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ExtremeBDS [4]
4 years ago
9

Please do number 1! I really need to finish it fast!!

Physics
2 answers:
Lady bird [3.3K]4 years ago
6 0
Answer: 1. there has to be a circle on the tip of a triangle.
Pavel [41]4 years ago
3 0

Answer:

(2)

Circle square,

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Select ALL of the following statements that provide evidence that there is friction acting on a cart moving along a level track.
Sati [7]

Answer:

1st and 4th one................

6 0
3 years ago
a missile is moving 1810 m/s at a 20.0 degree angle. it needs to hit a target 19,500 m away in a 32.0 degree direction in 9.20 s
Ket [755]

Answer:

112 m/s², 79.1°

Explanation:

In the x direction, given:

x₀ = 0 m

x = 19,500 cos 32.0° m

v₀ = 1810 cos 20.0° m/s

t = 9.20 s

Find: a

x = x₀ + v₀ t + ½ at²

19,500 cos 32.0° = 0 + (1810 cos 20.0°) (9.20) + ½ a (9.20)²

a = 21.01 m/s²

In the y direction, given:

y₀ = 0 m

y = 19,500 sin 32.0° m

v₀ = 1810 sin 20.0° m/s

t = 9.20 s

Find: a

y = y₀ + v₀ t + ½ at²

19,500 sin 32.0° = 0 + (1810 sin 20.0°) (9.20) + ½ a (9.20)²

a = 109.6 m/s²

The magnitude of the acceleration is:

a² = ax² + ay²

a² = (21.01)² + (109.6)²

a = 112 m/s²

And the direction is:

θ = atan(ay / ax)

θ = atan(109.6 / 21.01)

θ = 79.1°

5 0
3 years ago
calculate the force required to take away a flat corcular plate of radius 0.01m from the surface of water. the surface tention o
leonid [27]

Answer:

Force = 0.0047175\ N

Explanation:

Given

T = 0.075N/m --- Surface Tension

r = 0.01m --- Radius

Required

Determine the required force

First, we calculate the circumference (C) of the circular plate

C= 2\pi r

C= 2 * \frac{22}{7} * 0.01m

C= \frac{2 * 22 * 0.01}{7}m

C= \frac{0.44}{7}m

C= 0.0629 m

The applied force is then calculated using;

Force = C * T

Force = 0.0629m * 0.075N/m

Force = 0.0047175\ N

8 0
3 years ago
Which force acts as an object to move it from rest or a constant straight-line motion?
podryga [215]

Answer: C

Explanation: The correct answer would be Inertial.  I take the quiz and got the answer rght!!

8 0
4 years ago
The animation shows a ball which has been kicked upward at an angle. Run the animation to watch the motion of the ball. Click in
sergejj [24]

Answer:

The acceleration of the ball is  a_y =  - 0.3672 \ m/s^2

Explanation:

From the question we are told that

       The maximum height the ball reachs is H_{max} =  42.24 \ m

       The horizontal component of the initial velocity of the ball is v_{ix} = 5.57 \ m/s

       The vertical component of the initial velocity of the ball is v_{iy} = = 16.18 m/s

The vertically motion of the ball can be mathematically represented as

       v_{fy}^2  =  v_{iy} ^2 + 2 a_{y} H_{max}

Here the final velocity at the maximum height is zero so v_{fy} = 0 \ m/s

Making the acceleration a_y the subject we have

        a_y =  \frac{v_{iy} ^2}{2H_{max}}

substituting values

      a_y =  - \frac{5.57^2}{2* 42.24}

      a_y =  - 0.3672 \ m/s^2

The negative sign shows that the direction of the acceleration is in the negative y-axis

6 0
3 years ago
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