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Eduardwww [97]
3 years ago
5

A high-speed flywheel in a motor is spinning at 500 rpm when a power failure suddenly occurs. The flywheel has mass 39.0 kg and

diameter 80.0 cm. The power is off for 32.0 s and during this time the flywheel slows due to friction in its axle bearings. During the time the power is off, the flywheel makes180 complete revolutions.
A. At what rate is the flywheel spinning when the power comes back on? (rad/s)

B. How long after the beginning of the power failure would it have taken the flywheel to stop if the power had not come back on? (s)

C. How many revolutions would the wheel have made during this time?

Physics
1 answer:
dimaraw [331]3 years ago
4 0

Answer:

a. 5.83 πrad/s

b. 49.03s

c. 408.67 πrad

Explanation:

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Explanation:

Given the following :

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Time (t) = √ (weight of string * Length) / weight attached to lower end * acceleration due to gravity

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Time = √3.2 / 9800

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<h3>Further explanation</h3>

Given

vo=initial velocity=0(from rest)

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t₃= 30 s

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Solution

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\tt d=vo.t+\dfrac{1}{2}at^2\\\\d=\dfrac{1}{2}\times 1\times 20^2\rightarrow vo=0\\\\d=200~m

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Explanation:

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