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Lunna [17]
3 years ago
6

Which of these kinds of interactions are broken when a liquid is converted to a gas? which of these kinds of interactions are br

oken when a liquid is converted to a gas? intermolecular interactions are broken when a liquid is converted to a gas. intramolecular interactions are broken when a liquid is converted to a gas. both of these interactions are broken?
Chemistry
2 answers:
Sonja [21]3 years ago
5 0
liquid  to  gas  intermolecular  interaction  are  broken  when  liquid  is  converted to  a  gas.Example  in  CH3COOH    liquid,  dispersion  forces, dipole-dipole  forces  and  hydrogen bonding are intermolecular  forces  that  must  be   overcomed  to  convert   C H3COOH  from  liquid  to  gas.
atroni [7]3 years ago
3 0

Answer: Option (a) is the correct answer.

Explanation:

Intermolecular interaction means the interactions present between two molecules. And, intramolecular interactions mean the interactions present within the molecules of a substance.

So, when interactions within a molecule that is, intramolecular interactions change then chemical properties of the substance changes.

On the other hand, when intermolecular interactions change then there occurs change in state of substance.

Thus, we can conclude that intermolecular interactions are broken when a liquid is converted to a gas.

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Describe the four types of fronts and the weather associated with each.
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The Four type is

Cold front

Warm front

Stationary front

Occluded front

3 0
3 years ago
What volume of a 0.33-M C12H22O11 solution can be diluted to prepare 25 mL of a solution with a concentration of 0.025 M?
Vsevolod [243]

The dilution formula can be used to find the volume needed

c1v1 = c2v2

Where c1 is concentration and v1 is volume of the concentrated solution

And c2 is concentration and v2 is volume of the diluted solution to be prepared

c1 - 0.33 M

c2 - 0.025 M

v2 - 25 mL

Substituting these values in the equation

0.33 M x v1 = 0.025 M x 25 mL

v1 = 1.89 mL

Therefore 1.89 mL of the 0.33 M solution needs to be diluted up to 25 mL to make a 0.025 M solution

7 0
3 years ago
25)
Taya2010 [7]

Answer:

The correct answer is B) electronegativities of the bonded atoms in a molecule of the compound .

Explanation:

When two atoms forming a bond differ in their electronegativities at that time bond polarity is generated

        In simple words a bond will be polar when the bonding electrons are not equally shared by two atoms.As a result the atom attract the bonding electron pair towards itself gain partial negative charge and the other atom gains partial positive charge.

       For HCl is a polar compound because H and Cl atom differ in their electronegativities,as a result the bonding electron pair is not shared equally by H and Cl atoms.

8 0
3 years ago
What forces hold network solids together?
ZanzabumX [31]

Answer:

Covalent solids, also called network solids, are solids that are held together by covalent bonds. As such, they need localized electrons (shared between the atoms) and therefore the atoms are arranged in fixed geometries. Distortion far from this geometry can only occur through a breaking of covalent sigma bonds.

8 0
3 years ago
Plesse help asap!!!​
Naily [24]

Answer:

4.4×10² cm³

Explanation:

From the question given above, the following data were obtained:

Diameter (d) = 68.3 mm

Height (h) = 0.120 m

Volume (V) =?

Next, we shall convert the diameter (i.e 68.3 mm) to cm.

This can be obtained as follow:

10 mm = 1 cm

Therefore

68.3 mm = 68.3 mm / 10 mm × 1 cm

68.3 mm = 6.83 cm

Therefore, the diameter 68.3 mm is equivalent 6.83 cm.

Next, we shall convert the height (i.e 0.120 m) to cm. This can be obtained as follow:

1 m = 100 cm

Therefore,

0.120 m = 0.120 m/ 1 m × 100 cm

0.120 m = 12 cm

Therefore, the height 0.120 m is equivalent 12 cm.

Next, we shall determine the radius of the cylinder. This can be obtained as follow:

Radius (r) is simply half of a diameter i.e

Radius (r) = Diameter (d) /2

r = d/2

Diameter (d) = 6.83 cm

Radius (r) =?

r = d/2

r = 6.83/2

r = 3.415 cm

Finally, we shall determine the volume of the cylinder as follow:

Radius (r) = 3.415 cm

Height (h) = 12 cm

Volume (V) =?

Pi (π) = 3.14

V = πr²h

V = 3.14 × (3.415) ² × 12

V = 440 cm³

V = 4.4×10² cm³

Therefore, the volume of the cylinder is 4.4×10² cm³

8 0
2 years ago
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