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Sladkaya [172]
3 years ago
5

A person's heartbeat is 68 beats per minute. If his/her heart beats 3.1e9 times in a lifetime, how long (in whole years) does th

e person live? Disregard leap years.
Chemistry
2 answers:
kari74 [83]3 years ago
8 0
To determine the number of years for a person to live, we can divide the total number of beats in a lifetime to the number of beats per minute. We first need to check if the units are similar so we can cancel them. We do as follows:

3.1x10^9 beats / 68 beats per minute = 45588235.29 minutes ( 1hr / 60 min ) ( 1 day/24hr) ( 1 year / 365 days ) = 87 years

Hope this answers the question. Have a nice  day.
nata0808 [166]3 years ago
6 0

Answer:

The person has lived 87 years long life.

Explanation:

Rate of the heart beat of the person = 68 beats/min

Let the age of the person be X.

Total heart beats in his X years of life = 3.1\times 10^9 beats

\frac{3.1\times 10^9 beats}{X}=68 beats/ min

X=\frac{3.1\times 10^9 beats}{68 beats/ min}

X = 45,588,235.29 min

1 year = 365 days

1 day = 24 hours

1 hours = 60 mins

1 year = 365 × 24 × 60 min  = 525,600 min

X = \frac{45,588,235.29}{525,600} year=86.73 years\approx 87 years

The person has lived 87 years long life.

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A worker is told her chances of being killed by a particular process are 1 in every 300 years. Should the worker be satisfied or
Pavlova-9 [17]

Answer:

(a) Yes, he should be worried. The Fatal accident rate (FAR) is too high according to standars of the industry. This chemical plant has a FAR of 167, where in average chemical plants the FAR is about 4.

(b) FAR=167 and Death poer person per year = 0.0033 deaths/year.

(c) The expected number of fatalities on a average chemical plant are one in 12500 years.

Explanation:

Asumming 50 weeks of work, with 40 hours/week, we have 2000 work hours a year.

In 300 years we have 600,000 hours.

With these estimations, we have (1/600,000)=1.67*10^(-6) deaths/hour.

If we have 2000 work hours a year, it is expected 0.0033 deaths/year.

1.67*10^{-6} \frac{deaths}{hour}*2000 \frac{hours}{year}=0.0033 deaths/year

The Fatal accident rate (FAR) can be expressed as the expected number of fatalities in 100 millions hours (10^(8) hours).

In these case we have calculated 1.67*10^(-6) deaths/hour, so we can estimate FAR as:

FAR=1.67*10^{-6} \frac{deaths}{hour}*10^{8}  hours=1.67*10^{2} =167

A FAR of 167 is very high compared to the typical chemical plants (FAR=4), so the worker has reasons to be worried.

If we assume FAR=4, as in an average chemical plant, we expect

4\frac{deaths}{10^{8} hour} *2000\frac{hours}{year}=8*10^{-5} \frac{deaths}{year}

This is equivalent to say

\frac{1}{8*10^{-5} } \frac{years}{death}=1.25*10^{4} \frac{years}{death} =12500 \, \frac{years}{death}

The expected number of fatalities on a average chemical plant are one in 12500 years.

4 0
3 years ago
Which statements correctly describe the rock cycle? Check all that apply.
pickupchik [31]

Answer: I italicize for checking

  1. <em>Rocks are preserved through the process.</em>
  2. <em>Rocks change from one type to another.</em>
  3. <em>Different rock groups are interrelated.</em>
  4. Rocks change from one type to another in a specific order.
  5. <em>Environmental conditions influence a change in rock type.</em>

Explanation:

Rocks are preserved, as in you can't destroy them completely, but no, they don't <em>stay </em>the same they change.

3 0
3 years ago
Calculate the mass of iron oxide that contains a trillion iron atoms
4vir4ik [10]
<h3>i think its help</h3><h3>iron ( III )</h3><h3>oxide ( Fe,O )</h3>
4 0
3 years ago
Select all the correct images<br><br> Select the atoms that belong to the same element
mezya [45]

Answer: Atoms with 11 protons, 10 neutrons and 11 electrons belong to the same element with 11 protons, 12 neutrons and 11 electrons.

Explanation:

Elements that contain same number of valence electrons belong to the same group. This is because they will have same reactivity (or properties) due to which they lie in the same group.

For example, element with 11 protons, 10 neutrons and 11 electrons is same as the element with 11 protons, 12 neutrons and 11 electrons.

Hence, both these atoms belong to the same element.

Thus, we can conclude that atoms with 11 protons, 10 neutrons and 11 electrons belong to the same element with 11 protons, 12 neutrons and 11 electrons.

3 0
3 years ago
Which type of compound is always an electrolyte?
Kruka [31]
An ionic compound is always an electrolyte
5 0
3 years ago
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