Question

A person's heartbeat is 68 beats per minute. If his/her heart beats 3.1e9 times in a lifetime, how long (in whole years) does the person live? Disregard leap years.

Answer 1

To determine the number of years for a person to live, we can divide the total number of beats in a lifetime to the number of beats per minute. We first need to check if the units are similar so we can cancel them. We do as follows:

3.1x10^9 beats / 68 beats per minute = 45588235.29 minutes ( 1hr / 60 min ) ( 1 day/24hr) ( 1 year / 365 days ) = 87 years

Hope this answers the question. Have a nice  day.

Answer 2

Answer:

The person has lived 87 years long life.

Explanation:

Rate of the heart beat of the person = 68 beats/min

Let the age of the person be X.

Total heart beats in his X years of life = $3.1\times 10^9 beats$

$\frac{3.1\times 10^9 beats}{X}=68 beats/ min$

$X=\frac{3.1\times 10^9 beats}{68 beats/ min}$

X = 45,588,235.29 min

1 year = 365 days

1 day = 24 hours

1 hours = 60 mins

1 year = 365 × 24 × 60 min  = 525,600 min

$X = \frac{45,588,235.29}{525,600} year=86.73 years\approx 87 years$

The person has lived 87 years long life.