Answer:
mass of CO₂ produced = 5.06 g of CO₂
Explanation:
Equation of the reaction: 2CH₃CH₃ + 5O₂ ---> 4CO₂ + 6H₂O
From the equation of the reaction, 2 moles of gaseous ethane reacts with 5 moles of oxygen gas to produce 6 moles of water.
molar mass of ethane = 30 g/mol
molar mass of oxygen gas = 32 g/mol
number of moles of ethane present in 1.8 g = 1.8/30 = 0.06 moles
number of moles of oxygen gas present in 4.6 g = 4.6/32 = 0.14375 moles
mole ratio of oxygen gas to ethane = 2.4 : 1
Therefore, oxygen is the limiting reactant
0.14375 moles of oxygen will react with 0.06 moles of ethane to produce 4/5 * 0.14375 moles of CO₂ = 0.115 moles of CO₂
molar mass of CO₂ = 44 g/mol
mass of CO₂ produced = 0.1725 * 44
mass of CO₂ produced = 5.06 g of CO₂
