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blondinia [14]
4 years ago
11

When a force of 15 newtons is applied to a stationary chair, it starts moving. What can you say about the frictional force betwe

en the chair and the floor of the room?
Physics
2 answers:
Afina-wow [57]4 years ago
3 0
Kinetic friction since the object starts moving
nataly862011 [7]4 years ago
3 0

Answer:

That the maximum static frictional force is 15 N

Explanation:

The static frictional force is the force of friction that acts on an object at rest on a surface, when the object is pushed by an external force. The static frictional force acts in the opposite direction to the external force, preventing the object to start moving unless the external force overcomes it.

Due to its nature, the magnitude of the static frictional force varies between zero (if no external force is applied) to a maximum value, defined as

F_s = \mu mg

where \mu is the coefficient of static friction, m is the mass of the object and g is the acceleration due to gravity.

The object starts to move only when the magnitude of the external force becomes larger than the maximum value of the static frictional force. In this problem, this happens when the external force is 15 N, so we can say that the maximum value of the static frictional force is 15 N.

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3 years ago
A trailer truck with a 2000 [kg] cab and a 8000 [kg] trailer is traveling on a level road at 90 [km/hr].The brakes on the traile
NeX [460]

Answer:

a)   t = 19.6 s, b) fr = 1.274 10⁴ N

Explanation:

This is a Newton's second law problem

Y Axis

for the cabin

        N₁-W₁ = 0

        N₁ = W₁

for the trailer

        N₂- W₂ = 0

        N₂ = W₂

X axis

for the cabin plus trailer, where friction is only in the cabin

         fr = (m₁ + m₂) a

the friction force equation is

        fr = μ N

we substitute

       μ N₁ = (m₁ + m₂) a

        μ m₁ g = (m₁ + m₂) a

        a = μ g    \frac{m_1}{m_1 + m_2}

         

let's calculate

         a = 0.65 9.8    \frac{2000}{2000+8000}

         a = 1,274 m / s²

a) to find the stopping distance we can use kinematics

         Let's slow down the sI system

         v₀ = 90 km / h (1000 m / 1km) (1h / 3600s) = 25 m / s

         v = v₀ - a t

when it is stopped its speed is zero

           0 = v₀ - at

           t = v₀ / a

           t = 25 / 1.274

           t = 19.6 s

b) the friction force is

           fr = 0.65 2000 9.8

          fr = 1.274 10⁴ N

This is the braking force and also the forces that couple the cars.

3 0
3 years ago
What is the maximum energy EmaxEmaxE_max stored in the capacitor at any time during the current oscillations
DanielleElmas [232]

Complete Question

An L-C circuit has an inductance of 0.350 H and a capacitance of  0.290 nF . During the current oscillations, the maximum current in the inductor is 2.00 A .

What is the maximum energy E_{max} stored in the capacitor at any time during the current oscillations?

Express your answer in joules.

Answer:

The value is   E_{max} =   0.7 J

Explanation:

From the question we are told that

   The inductance is L  =  0.350 \  H

    The capacitance is C =  0.290 \ nF =  0.290 *10^{-9 } \ F

   The current is  I  = 2 \ A

Generally the maximum energy is mathematically represented as

        E_{max} =  \frac{1}{2}  *  L  *  I^2

=>       E_{max} =  \frac{1}{2}  *   0.350  *  2^2

=>     E_{max} =   0.7 J

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4 years ago
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I don't know the name, but the opposite of gravity, if that helps!

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3 years ago
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