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muminat
3 years ago
10

What is the smallest radius of an unbanked (flat) track around which a bicyclist can travel if her speed is 23 km/h and the coef

ficient of static friction between tires and track is 0.24?

Physics
2 answers:
Firdavs [7]3 years ago
8 0

Explanation:

Below is an attachment containing the solution.

Zina [86]3 years ago
3 0

Answer:

R=17.4m

Explanation:

Given data

Speed v=23 km/h =6.4 m/s

Coefficient of static friction μs=0.24

The acceleration experienced by bicycle is centripetal acceleration  by:

\alpha =\frac{v^2}{R}

This acceleration is only due to static friction force given by:

f=m\frac{v^2}{R}

The maximum value of the static friction force given by

f_{s.max}=u_{s}F_{N}\\Where\\F_{N}=mg

Therefore when the car is on verge of sliding:

f=f_{s.max}\\m\frac{v^2}{R}=u_{s}mg

Therefore the minimum radius the bicycle can move without sliding is:

R=\frac{v^2}{u_{s}g}\\ R=\frac{(6.4m/s)^2}{0.24(9.8m/s^2)} \\R=17.4m

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