Answer:
Explanation:
Using the atomic mass of pluonium atoms (244 g/mol), you can calculate the number of atoms in 47.0 g. Then, knowing that each plutonium atom has 96 protons, you calculate the number of protons in the 47.0 g sample. Finally, using the positive charge of one proton, you calculate the total positive charge in the 47.0 g of plutonium.
<u>1. Number of atoms of plutonium in 47.0 g</u>
- Number of moles = mass / atomic mass = 47.0 g / 244 = 0.1926 moles
- Number of atoms = number of moles × 6.022 × 10²³ atoms/mol
- Number of atoms = 0.1926 mol × 6.022 × 10²³ atoms/mol = 1.15998×10²³ atoms
<u>2. Number of protons</u>
- Number of protons = 1.15998×10²³ atoms × 96 protons/atom = 1.11385×10²⁵ protons
<u>3. Charge</u>
<u />
- Charge = charge of one proton × number of protons
- Charge = 1.602×10⁻¹⁹ C/proton × 1.11385×10²⁵ protons = 1.78×10⁶C
Answer:
option b
Explanation:
from the given formula, s=d/t
make t the subject of the formula we have
t=d/s
5/100
0.5
Answer:
Vb = k Q / r r <R
Vb = k q / R³ (R² - r²) r >R
Explanation:
The electic potential is defined by
ΔV = - ∫ E .ds
We calculate the potential in the line of the electric pipe, therefore the scalar product reduces the algebraic product
VB - VA = - ∫ E dr
Let's substitute every equation they give us and we find out
r> R
Va = - ∫ (k Q / r²) dr
-Va = - k Q (- 1 / r)
We evaluate with it Va = 0 for r = infinity
Vb = k Q / r r <R
We perform the calculation of the power with the expression of the electric field that they give us
Vb = - int (kQ / R3 r) dr
We integrate and evaluate from the starting point r = R to the final point r <R
Vb = ∫kq / R³ r dr
Vb = k q / R³ (R² - r²)
This is the electric field in the whole space, the places of interest are r = 0, r = R and r = infinity
The image is always virtual and erect. The image is highly diminished or point sized. It is always formed between F and P.
Answer:
she used force to swing her ball all way back
Explanation: