Question

NEED HELP FAST ILL MARK BRAINLIEST AND RATE 5 STARS AND SAY THANK YOU

Answer 1

Acceleration = (change in speed)/(time for the change)

Change in speed = (end speed) - (start speed)

Change in speed = (10 m/s) - (20 m/s) = -10 m/s

Time for the change = 5.00 seconds

Acceleration = (-10 m/s) / (5 sec)

Acceleration = -2 m/s²

That's choice-A .

Answer 2

Hello!

A car going 72.0 km/h (20.0 m/s) slows down to 36.0 km/h (10.0 m/s) in 5.00 seconds. Calculate the acceleration in m/s² .

We have the following data:

a (acceleration) = ? (in m/s²)

Vi (initial velocity) = 20 m/s

Vf (final velocity) = 10 m/s

Δv (velocity variation) = Vf - Vi , then:

$\Delta{V} = V_f - V_i$

$\Delta{V} = 10 - 20$

$\Delta{V} = - 10\:m/s$

Δt (time variation) = 5 s

We apply the data to the average acceleration formula, see:

$a = \dfrac{\Delta{V}}{\Delta{T}}$

$a = \dfrac{- 10\:\dfrac{m}{s} }{5\:s}$

$\boxed{\boxed{a = - 2\:\dfrac{m}{s^2} }}\end{array}}\qquad\checkmark$

Answer:

A. -2.00

_______________________________

I Hope this helps, greetings ... Dexteright02! =)