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Umnica [9.8K]
3 years ago
11

If you double the wavelength, the electromagnetic radiation energy will double. The energy of the electromagnetic radiation will

halve if you halve the wavenumber. When the frequency of the light is doubled, its energy will .
Physics
1 answer:
Sedbober [7]3 years ago
7 0

Answer:

It's energy will double.

Explanation:

This is because energy, E, is related to frequency, f, by:

E = hf

Where h = Planck's constant

So, double frequency will be 2f

=> E(2f) = 2hf = 2E.

Hence, energy is doubled.

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What’s the kinetic energy of the object? Use .
Fynjy0 [20]

Answer:

18joules

Explanation:

1/2 of 4=2

2 multiply by 9= 18 joules

4 0
3 years ago
Identify the false statement: Select one:
svet-max [94.6K]

Answer:

D) Synthesizers have always had a well-established presence in standard ensembles

Explanation:

As synthesizers are electronic music instruments that can create the sounds of many different musical instruments, they have been seen as a threat to many musicians since their invention.

8 0
3 years ago
Read 2 more answers
Electrons flow from the negative terimal of a
gizmo_the_mogwai [7]

Answer:

Option B

Explanation:

The electrons flow from negative terminal of a battery to the positive terminal because as the charge of electron is negative, it will get repelled by the negative terminal of the battery

Conventional flow actually assumes that the current flows out of the positive terminal, through the circuit and into the negative terminal of the battery

It actually says that direction of flow of current is in opposite direction to the direction of flow of electrons

The direction of current will not change even a resistor is placed in the circuit and it generates a potential difference across the resistor

But the current tries to move in such a way in which there will be less resistance to the flow

3 0
3 years ago
In part B of the lab, when the current flows through the orange part of the wire from right to left, the wire deflects (or moves
s2008m [1.1K]

Answer:

This seems to be incomplete, as we do not have any information about the magnetic field surrounding the wire, but we can answer in a general way.

We know that for a wire of length L, with a current I, and in a magnetic field B, the force can be written as:

F = L*(IxB)

if we define the right as the positive x-axis, and knowing that the current flows to the right, we can write:

I = i*(1, 0, 0)

And the field will be some random vector that can't be parallel to the current because in that case, we do not have any force.

To find the direction of the force, which will tell us the direction in which the wire deflects or moves, first, we need to point with our thumb in the direction of the current, in this case, to the right.

Now, with the hand open, using the tip of our other fingers we point in the direction of the magnetic field.

For example, if the magnetic field is in the positive z-axis, we will point upwards.

Now the palm of our hand tells us in which direction the force is applied.

This is the right-hand rule.

For example, in the case that the current goes to the right and the magnetic field is upwards, we could see that the force is to the front.

7 0
3 years ago
Train cars are coupled together by being bumped into one another. Suppose two loaded cars are moving toward one another, the fir
tia_tia [17]

Answer:

7560 Joules

Explanation:

m_1 = Mass of first car = 1.5\times 10^5\ kg

m_2 = Mass of second car = 2\times 10^5\ kg

u_1 = Initial Velocity of first car = 0.3 m/s

u_2 = Initial Velocity of second car = -0.12 m/s

v = Velocity of combined mass

As linear momentum of the system is conserved

m_1u_1 + m_2u_2 =(m_1 + m_2)v\\\Rightarrow v=\frac{m_1u_1 + m_2u_2}{m_1 + m_2}\\\Rightarrow v=\frac{1.5\times 10^5\times 0.3 + 2\times 10^5\times -0.12}{1.5\times 10^5 + 2\times 10^5}\\\Rightarrow v=0.06\ m/s

Energy lost is

\Delta E=\Delta E_i-\Delta E_f\\\Rightarrow \Delta=\frac{1}{2}(m_1u_1^2 + m_2u_2^2-(m_1+m_2)v^2)\\\Rightarrow \Delta=\frac{1}{2}(1.5\times 10^5\times 0.3^2 + 2\times 10^5\times (-0.12)^2-(1.5\times 10^5 + 2\times 10^5)\times 0.06^2)\\\Rightarrow \Delta=7560\ J

The Energy lost in the collision is 7560 Joules

7 0
3 years ago
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