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anzhelika [568]
3 years ago
9

A 0.100-kilogram apple hangs in a tree 1.50 meters above the ground. Ignoring frictional effects, the total mechanical energy of

the apple is _____.
A)0.00 J
B)less than 1.47 J but more than 0.00 J
C)exactly 1.47 J
D)more than 1.47 J
correct answer :c
Chemistry
2 answers:
prohojiy [21]3 years ago
8 0

Answer:

4455625c632

Explanation:

haha i answered

Ivan3 years ago
4 0

Answer:

C)exactly 1.47 J

Explanation:

The mechanical energy of a body or a system is the sum of its potential energy and kinetic energy

E_m=E_p+E_k

Data

m= 0.1Kg\\h=1.50m\\g(gravity)=9.8m/s^2

To find the mechanical energy we must first find out what is its potential energy and its kinetic energy

E_p= m.g.h\\E_p=0.1Kg. 9.8m/s^2.1.50m\\E_p= 1.47J

E_k= \frac{1}{2}m.V^2

As we observe in the formula the kinetic energy depends on the speed of the body, but in this case the body is not moving, it is only found hanging at rest, therefore its speed is zero

E_k= \frac{1}{2}0.1Kg.0\\ E_k= 0

as the body has no speed the kinetic energy is zero

Now we calculate the mechanical energy

E_m=E_p+E_k\\E_m=1.47J+0\\E_m=1.47J

The mechanical energy is 1.47J. The correct option is C

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