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melamori03 [73]
3 years ago
7

Which changes will increase the rate of reaction during combustion? decreasing the area of contact between the reactants adding

more oxygen to the reaction removing heat from the reaction changing the reactants from solid form to powdered form lowering the exposure of the reactants to air
Physics
2 answers:
alekssr [168]3 years ago
4 0
<h3><u>Answer;</u></h3>
  • <em>Adding more oxygen to the reaction </em>
  • <em>Changing the reactants from solid form to powdered form </em>
<h3><u><em>E</em></u><u>xplanation</u>;</h3>
  • <em><u>The rate of chemical reaction depends on a number of factors,</u></em> these factors are factors such as temperature, concentration of reactants, concentration of reactants and using catalyst among others.
  • <u><em>Increasing temperature in a chemical reactions increases the rate of reaction as there will be increased collision of particles of the reactants thus more products will be formed. </em></u>
  • <u><em>Increasing the surface area of the reactants also increase the rate of reaction</em></u>, this is done by changing the reactants from the form of solid into powdered form thus, there will be more collisions between reactants particles and this will enhance formation of products.
  • <em><u>Increasing the concentration of reactants, </u></em>for example increasing the amount of oxygen in the reaction which one of the reactant, will increase the rate of reaction.
STALIN [3.7K]3 years ago
3 0
The correct answer is B. The addition of oxygen will increase the rate of combustion. oxygen and raw material (fuel) are the substrates for the combustion process, therefore, increase in the same will obviously increase combustion rate. Carbon in the fuel is converted into carbon dioxide and heat. 
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The electromagnetic spectrum consists of many waves which are made up of electric field and the magnetic field.

It is said that the electromagnetic wave behaves like particle as well as the wave.

The particle like pieces of the wave are called photons which contains the energy of the wave and the electromagnetic waves are primarily decided by the wavelength and the frequency of the wave.

The group of electromagnetic waves are known as electromagnetic spectrum.

The electromagnetic wave in the order of increasing wavelength are Gamma Rays <  X-rays < UV rays < visible rays < infrared rays < microwaves < radio waves.

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8 0
1 year ago
a wave having a wavelength of 4.7 meters and an amplitude of 2.5 meters travels a distance of 28 meters in 7 seconds. determine
Aleksandr [31]

Answer:

<h2>T(Period) = 1.33s</h2><h2>f(Frequency) = 0.75Hz (cycles/second)</h2>

Explanation:

<h2>Given:</h2><h2 /><h2>λ = 4.0m</h2><h2>Amplitude = 25m</h2><h2>d = 24m</h2><h2>s = 8.0s</h2><h2 /><h2>Required:</h2><h2>f = ?</h2><h2>T = ?</h2><h2 /><h2>Analysis:</h2><h2>v = λf</h2><h2>f =N/t</h2><h2>T = 1/f</h2><h2 /><h2>v = d/t</h2><h2 /><h2>Solve:</h2><h2>v = d/t = 24/8.0 → v = 3.0m/s</h2><h2>v =λf → f = v/λ = 3.0/4.0 → f = 0.75Hz</h2><h2>T = 1/f = 1/0.75 → T = 1.33s</h2><h2 /><h2>Hopes this helps. Mark as brainlest plz!</h2>
4 0
3 years ago
A 900 kg car pushes a 2400 kg truck that has a dead battery. when the driver steps on the accelerator, the drive wheels of the c
Wewaii [24]
A)0
b)magnitude of the force on the car is 500n
5 0
3 years ago
A square plate of copper with 47.0 cm sides has no net charge and is placed ina region of uniform electric field of 75.0 kN/C di
timurjin [86]

Answer:

(a) Charge density σ=6.6375×10²nC/m²

(b) Total charge Q=1.47×10²nC

Explanation:

Given Data

A=47.0 cm =0.47 m

Electric field E=75.0 kN/C

To find

(a) Charge density σ

(b)Total Charge Q

Solution

For (a) charge density σ

From Gauss Law we know that

Φ=Q/ε₀.......eq(i)

Where

Φ is electric flux

Q is charge

ε₀ is permittivity of space

And from the definition of flux

Φ = EA

The flux is  electric field passing  perpendicularly through the surface

Put the this Φ in equation(i)

EA =Q/ε₀

where Q(charge)=σA

EA=(σA)/ε₀

E=σ/ε₀

σ=ε₀E

=(8.85*10^{-12} )*(75.0*10^{3} )\\=6.6375*10^{-7} C/m^{2}\\=6.63*10^{2}nC/m^{2}

σ=6.6375×10²nC/m²

For (b) total charge Q

Q=σA

Q=(6.6375*10^{2} nC/m^{2} )(0.47m)^{2}\\ Q=1.47**10^{2}nC

6 0
3 years ago
An easy 20 points + brainiest.
Papessa [141]

Answer:

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2 years ago
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