Since the factory will be producing 100,000 kilograms of cement, using the relation 1000 kg of cement = 900 kg of CO2, then the factory will be emitting 90,000 kg of CO2 at the same time. To counteract the emission, a tree can remove 6 kg of CO2 per day. Dividing 90,000 kg by 6 kg to know the number of trees, we need 15000 trees to counter the emission. Since 1 acre of land holds 200 trees, we need 75 acres of land to hold the 15000 trees.
Answer:
The acceleration of each of the two blocks and the tension in the rope are 5.92 m/s and 147.44 N.
Explanation:
Given that,
Mass = 12.0 kg
Angle = 31.0°
Friction coefficient = 0.158
Mass of second block = 38.0 kg
Using formula of frictional force
....(I)
Where, N = normal force

Put the value of N into the formula


Put the value of N in equation (I)


Now, Weight of second block



The horizontal force is


....(II)
(I). We need to calculate the acceleration



(II). We need to calculate the tension in the rope



Hence, The acceleration of each of the two blocks and the tension in the rope are 5.92 m/s and 147.44 N.
Answer:
RMS voltage is 113.1370 V
frequency is 780.685 Hz
voltage is −158.66942 V
maximum current is 2.9739 A
Explanation:
Given data
∆V = 160.0 sin(495t) Volts
so Vmax = 160
and angular frequency = 495
time t = 1/106 s
resistor R = 53.8 Ω
to find out
RMS voltage and frequency of the source and voltage and maximum current
solution
we know voltage equation = Vmax sin ωt
here Vmax is 160 as given equation in question
so RMS will be Vmax / √2
RMS voltage = 160/ √2
RMS voltage is 113.1370 V
and frequency = angular frequency / 2π
so frequency = 497 / 2π
frequency is 780.685 Hz
voltage at time (1/106) s
V(t) = 160.0 sin(495/ 108)
voltage = −158.66942 V
so current from ohm law at resistor R 53.8 Ω
maximum current = voltage max / resistor
maximum current = 160 / 53.8
maximum current = 2.9739 A
Explanation:
When a bullet is fired from a rifle, the actual firing makes a distinctive sound, but people at a distance may hear a second because the bullet creates a shock wave , a little sonic boom( speed of this sonic boom is greater than the speed of sound). It is this sound only that is heard by the people at a distance from the gun.