In comparison to a distribution with a standard deviation of 5, one has a curve with a higher peak. The variability will be greater the larger the standard deviation. It denotes increased variability in a distribution with a standard deviation of 5.
<h3>What do you mean by the term standard deviation?</h3>
The term "standard deviation" (or "") refers to a measurement of the data's dispersion from the mean. A low standard deviation implies that the data are grouped around the mean, whereas a large standard deviation shows that the data are more dispersed. In contrast, a high or low standard deviation indicates that the data points are, respectively, above or below the mean. A standard deviation that is close to zero implies that the data points are close to the mean. the curve at the top is more dispersed and has a greater standard deviation than the curve at the bottom, which is more concentrated around the mean and has a lower standard deviation.
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Answer:
The solute is oxygen
The solvent is water
Explanation:
A solvent is any chemical substance that dissolves other chemical substances, while a solute refers to any chemical substance that dissolves in other chemical substances. The best way to know when a chemical substance dissolves in another chemical substance is when a solid or gas dissolves in water. The solid or the gas can now be referred to as the solute and it will be shown to be in the the aqueous state, while the solvent is usually shown to be in the liquid state in any chemical equation.
Let us use the particular example of the dissolution of oxygen gas in water as shown below;
O2(g) + H2O(l)⇄O2(aq) + H2O(l)
The aqueous oxygen is the solute while the liquid water is the solvent.
Also, the substance having a smaller mass must be the solute and the substance having the larger mass must be the solvent.
Wein’s Law, search it up if you need more info
Answer:
D = 4 m
Explanation:
Speed of cart in air track v₁ = 0.5 m/s
Speed of cart moved when air is turned off v₂= 1 m/s
The distance travelled by the cart is d₁ = 1 m
Work done (W) = F x d
Work done is equal to the kinetic energy
F x d = 1/2mv²
velocity is directly proportional to distance
therefore,
v₁²/ v₂² = d₁ / d₂
d₂ = d₁v₂² / v₁²
= 1 m x (1 m /s)² / (0.5 m/s)²
= 4 m
