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stiv31 [10]
2 years ago
13

A wave travels down the length of a 25-meter rope in 5.0 seconds. The speed of the wave is _____.

Physics
2 answers:
Luden [163]2 years ago
7 0

Answer:

The speed of the wave is 50 m/s

Explanation:

The wave traveled through the length in 5 seconds,  the speed is the distance  that the wave travel at one second.

For know the speed we will use the following equation:

V = X/T

Where V is speed, X is distance and T is time).

From the information in the statement:, we know that 25 meters is our distance  and 5 seconds is our time .

Replacing this values in the initial equation, we get:

V = X/T

V= 25 meters/5 seconds

V= 5 meters/s econd or 5m/s

Finally, the speed of the wave is 50 m/s.

Alborosie2 years ago
4 0
Speed
= (distance covered) / (time to cover the distance)

= (25 m) / (5.0 sec) = 5.0 m/s .
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A 41 kg girl and a 5.0 kg sled are on the frictionless ice of a frozen lake, 15 m apart but connected by a rope of negligible ma
goldfiish [28.3K]

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F=ma

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(b) 0.098 m/s^2

According to Newton's third law (action-reaction law), since the girl exerts a force on the sled, then the sled exerts an equal and opposite force on the girl as well. This means that the force exerted on the girl is also F = 4.0 N. As before, we can calculate the acceleration of the girl by using Newton's second law:

F=ma

where

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(c) 5.8 s

Taking the initial position of the girl as x = 0, the position at time t of the girl is given by:

x(t)=\frac{1}{2}a_g t^2

where a_g = 0.098 m/s^2 is the acceleration of the girl.

The sled starts instead its motion from x = 15 m, so its position at time t is given by

x'(t)=15-\frac{1}{2}a_s t^2

where a_s=0.8 m/s^2 is the acceleration of the sled, and the negative sign is due to the fact that the sled accelerates in opposite direction to the girl's acceleration.

The girl and the sled meet when x(t) = x'(t). So, we find:

\frac{1}{2}a_g t^2=15-\frac{1}{2}a_s t^2\\(a_g+a_s) t^2=30 m\\t=\sqrt{\frac{30 m}{a_g+a_s}}=\sqrt{\frac{30 m}{0.8 m/s^2+0.098 m/s^2}}=5.8 s

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