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stiv31 [10]
3 years ago
13

A wave travels down the length of a 25-meter rope in 5.0 seconds. The speed of the wave is _____.

Physics
2 answers:
Luden [163]3 years ago
7 0

Answer:

The speed of the wave is 50 m/s

Explanation:

The wave traveled through the length in 5 seconds,  the speed is the distance  that the wave travel at one second.

For know the speed we will use the following equation:

V = X/T

Where V is speed, X is distance and T is time).

From the information in the statement:, we know that 25 meters is our distance  and 5 seconds is our time .

Replacing this values in the initial equation, we get:

V = X/T

V= 25 meters/5 seconds

V= 5 meters/s econd or 5m/s

Finally, the speed of the wave is 50 m/s.

Alborosie3 years ago
4 0
Speed
= (distance covered) / (time to cover the distance)

= (25 m) / (5.0 sec) = 5.0 m/s .
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No

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7 0
3 years ago
The photo shows a clay pot being made on a spinning potter's wheel. What
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Answer:

A

Explanation:

Shape the pot so that it has a wider bottom

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3 years ago
Water, which we can treat as ideal and incompressible, flows at 12 m/s in a horizontal pipe with a pressure of 3.0 x 10^4 Pa. If
frez [133]

Answer:

p2 = 9.8×10^4 Pa

Explanation:

Total pressure is constant and PT = P = 1/2×ρ×v^2  

So p1 + 1/2×ρ×(v1)^2 = p2 + 1/2×ρ×(v2)^2

from continuity we have ρ×A1×v1 = ρ×A2×v2  

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and  

r2 = 2×r1

then:

A2 = 4×A1  

so,

v2 = (v1)/4  

then:

p2 = p1 + 1/2×ρ×(v1)^2 - 1/2×ρ×(v2)^2 = p1 + 1/2×ρ×(v1)^2 - 1/2×ρ×(v1/4)^2  

p2 = 3.0×10^4 Pa + 1/2×(1000 kg/m^3)×(12m/s)^2 - 1/2×(1000kg/m^3)×(12^2/16)  

     = 9.75×10^4 Pa

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Therefore, the pressure in the wider section is 9.8×10^4 Pa

5 0
3 years ago
For a bronze alloy, the stress at which plastic deformation begins is 294 MPa and the modulus of elasticity is 121 GPa. (a) What
FromTheMoon [43]

Answer:

a) load in Newton is 96,138 b) 129.314mm

Explanation:

Stress = force/ area (cross sectional area of the bronze)

Force(load) = 294*10^6*327*10^-6 = 96138N

b) modulus e = stress/ strain

Strain = stress/ e = (294*10^6)/ (121*10^ 9) = 2.34* 10^ -3

Strain = change in length/ original length = DL/ 129

Change in length DL = 129 * 2.34*10^ -3 = 0.31347

Maximum length = change in length + original length = 129.314mm

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