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Degger [83]
3 years ago
12

What would be the final size of a balloon, at -18*C, if the initial volume is 2.0 L and the initial temperature is 20*C?

Physics
1 answer:
Anuta_ua [19.1K]3 years ago
7 0

Answer:

1.7 L

Explanation:

PV = nRT

If P, n, and R are constant:

V₁ / T₁ = V₂ / T₂

(2.0 L) / (293.15 K) = V / (255.15 K)

V = 1.7 L

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Which description is evidence of chemical weathering?
Gelneren [198K]

Answer:

b.

Explanation: I do not know much about this but the answer that i think it is was b.

8 0
3 years ago
A research submarine has a 20-cm-diameter window that is 9.0 cm thick. The manufacturer says the window can withstand forces up
Ratling [72]

Answer:

The maximum safe depth in salt water is 3758.2 m.

Explanation:

Given that,

Diameter = 20 cm

Radius = 10 cm

Thickness = 9.0 cm

Force F = 1.2\times10^{6}\ N

Inside pressure = 1.0 atm

We need to calculate the area

Using formula of area

A=\pi\times r^2

Put the value into the formula

A=\pi\times(10\times10^{-2})^2

A=0.0314\ m^2

We need to calculate the pressure

Using formula of pressure

P=\dfrac{F}{A}

Put the value into the formula

P=\dfrac{1.2\times10^{6}}{0.0314}

P=38216560.50\ Pa

P=3.8\times10^{7}\ Pa

We need to calculate the maximum depth

Using equation of pressure

P=P_{atm}+\rho gh

h=\dfrac{P-P_{atm}}{\rho g}

Put the value into the formula

h=\dfrac{3.8\times10^{7}-101325}{1029\times9.8}

h=3758.2\ m

Hence, The maximum safe depth in salt water is 3758.2 m.

4 0
3 years ago
An electron is initially at rest in a uniform electric field having a strength of 1.85 × 106 V/m. It is then released and accele
kirza4 [7]

Answer:

W = 462.5 keV

Explanation:

As we know that when electron moved in electric field then work done by electric field must be equal to the change in kinetic energy of the electron

So here we have to find the work done by electric field on moving electron

So we have

F = qE

F = (1.6 \times 10^{-19})(1.85 \times 10^6)

F = 2.96 \times 10^{-13} N

now the distance moved by the electron is given as

d = 0.25 m

so we have

W = F.d

W = (1.6 \times 10^{-19})(1.85 \times 10^6)(0.25)

W = 7.4 \times 10^{-14} J

now we have to convert it into keV units

so we have

1 keV = 1.6 \times 10^{-16} J

W = 462.5 keV

5 0
3 years ago
To improve your cardiovascular fitness:
RoseWind [281]
C.Perform push ups and curl-ups daily
4 0
3 years ago
Read 2 more answers
Yamin is running 50 feet of No. 14 wire (with a cross section of 4,110 cmils) to a load that draws current of 11 amps. What appr
castortr0y [4]

Resistance per 1000 feet for gauge 14 wire is given as

R = 2.525 ohm

now if wire is of length 50 feet only then the resistance is given as

R = \frac{2.525}{1000}\times 50

R = 0.126 ohm

now if 11 A current flows through the wire then the voltage drop is given by ohm's law

V = iR

V = 11 \times 0.126

V = 1.4 Volts

so most appropriate answer in given options is

A. 1.8 Volts

8 0
3 years ago
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