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krek1111 [17]
3 years ago
12

A car is going along a circular road at a constant speed. The radius of the curve is 242 m, and the car takes 1.3 minutes to com

plete one round. Calculate its centripetal acceleration in m/s^2
Physics
1 answer:
Dvinal [7]3 years ago
6 0

Answer:

a_c=1.57\frac{m}{s^2}

Explanation:

In order to find its centripetal acceleration we need to use the next equation:

a_c=\frac{v^2}{r}

So, we need to find its velocity in first place. Considering that the time T required for one complete revolution is called the period. For  constant speed is given by:

T=\frac{2\pi r}{v}

Solving for v, considering that in this case T=1.3min=78s, and r=242

v=\frac{2\pi *(242)}{78} =19.49398518m/s

Finally, replacing v in the centripetal acceleration equation:

a_c=\frac{(19.49398518)^{2} }{242}=1.570311811m/s^2

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\underline {\huge \boxed{ \sf \color{skyblue}Answer :  }}

<u>Given :</u>

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\:  \:

\tt \large {\color{purple}     ↬ }  \:  \:  \:  \:  \:  I_{DSS} = 10mA

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\tt \large {\color{purple}     ↬ }  \:  \:  \:  \:  \:  V_{GS(off)} = -6V

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\tt \large {\color{purple}     ↬ }  \:  \:  \:  \:  \:  V_{GS} =   {?}

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<u>Let's Slove :</u><u> </u>

  • \tt \large  I_{D} = I_{(DSS)}  (1 -   \frac {V_{GS}}{V_{GS(off)}} )^{2}

\:  \:  \:

  • \tt \large \: V_{GS} = (1 -  \frac{ \sqrt{I_D} }{ \sqrt{I_{DSS}} } ) \times  V_{GS(off)}

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Answer:

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