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3 years ago

If a solid is placed in a liquid and lots of bubbles are formed, what type of reaction has occurred?

Chemistry

2 answers:

BigorU [14]3 years ago

7 0

B___________________________________________

sveta [45]3 years ago

5 0

Your answer is going to be B.

Any time you see bubbles in a reaction (other than from boiling) it's automatically a chemical reaction.

I hope I was able to help. Best of luck.

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When calcium reacts with tellurium to form an ionic compound, each metal atom loses electron(s) and each nonmetal atom gains ele

Finger [1]

Answer:

When calcium reacts with tellurium it will donates its two electrons and these two electron will be accepted by tellurium.

There must be 1 calcium atom for every 1 tellurium atom in the reaction.

Explanation:

Calcium has atomic number of 20. Its electronic configuration is given as:

$[Ca]=1s^2 2s^2 2p^6 3s^2 3p^6 4s^2$

Calcium atom will loose 2 elections to attain electronic configuration of noble gas.

$[Ca^{2+}]=1s^2 2s^2 2p^6 3s^2 3p^6 4s^0$

$Ca\rightarrow Ca^{2+}+2e^-$

Tellurium has atomic number of 52. Its electronic configuration is given as:

$[Te]=1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4s^24p^6 4d^{10} 5s2 5p4$

Tellurium atom will gain 2 elections to attain electronic configuration of noble gas.

$[Te^{2-}]=1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4s^24p^6 4d^{10} 5s2 5p6$

$Te+2e^-\rightarrow Te^{2-}$

So, when calcium reacts with tellurium it will donates its two electrons and these two electron will be accepted by tellurium.

$Ca^{2+}+Te^{2-}\rightarrow CaTe$

There must be 1 calcium atom for every 1 tellurium atom in the reaction.

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Answer:

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