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zloy xaker [14]
3 years ago
6

Which components can be found in both comparative and experimental investigations, but are never found in descriptive investigat

ions? Check all that apply.
- question
- hypothesis
- variables
- control group
- prediction
- conclusion
Chemistry
2 answers:
Reptile [31]3 years ago
6 0

Answer:

HYPOTHESIS, VARIABLES, AND CONTROL GROUP

Explanation:

YOUR WELCOME :)

alex41 [277]3 years ago
4 0

Answer:

Hypothesis and Variables

Explanation:

I just took the quiz

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true

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What are the Lewis definitions of an acid and a base? In what way are Bronsted definitions? they more general than the In terms
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Explanation:

Lewis definition of Acids and Bases

Chemical species which are capable of accepting electron pairs or donating protons are called Lewis acid.

Chemical species which are capable of donating electron pairs or accepting protons are called Lewis base.

Bronsted definition of acids and bases

Chemical species which are capable of donating H+ are called Bronsted acids.

Chemical species which are capable of accepting H+ are called Bronsted bases.

So all Bronsted acids are Lewis acids but all Lewis acids are not Bronsted acids.

For a chemical species to behave as Lewis acid, they must have:

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For example, in BF3, octet of boron is incomplete, so it can accept a pair of electron and behaves as Lewis acid.

For a chemical species to behave as Lewis base, they must have:

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For example, NH3 and OH, both N and O have lone pairs of electrons, hence behave as Lewis base.

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3 years ago
Humans have used rocks in the creation of tools and building materials true or flase
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True, if you would like an example look at Indian arrow heads or early architecture all use rocks.
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3 years ago
Read 2 more answers
a 25.5 liter balloon holding 3.5 moles of carbon dioxide leaks. If we are able to determine that 1.9 moles of carbon dioxide esc
kap26 [50]

Answer:

11.66 L.

Explanation:

  • We can use the general law of ideal gas: <em>PV = nRT.</em>

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

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<em>(V₁n₂) = (V₂n₁).</em>

V₁ = 25.5 L, n₁ = 3.5 mol.

V₂ = ??? L, n₂ = 3.5 mol - 1.9 mol = 1.6 mol.

<em>∴ V₂ = (V₁n₂)/(n₁)</em> = (25.5 L)(1.6 mol)/(3.5 mol) =<em> 11.66 L.</em>

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