Question

A particular form of electromagnetic radiation has a frequency of 8.11 x 10^14 hz. What is the energy in joules of one quantum of this radiation?

Answer 1

E = hxf, où h = constante de Planck = 6,626 x 10 ^ -34Js 

E = 6,626 x 10 ^ -34 x 8.11 x 10 ^ 14 = 5.373 10^ -19 J  

Hope this answers your question, Kimmyers14!

Answer 2

Answer:

Energy, $E=5.37\times 10^{-19}\ J$

Explanation:

The frequency of the electromagnetic radiation, $f=8.11\times 10^{14}\ hz$

We need to find the energy of one quantum of this radiation. The energy and frequency follows the following relationship as :

$E=h\times f$

$E=6.63\times 10^{-34}\times 8.11\times 10^{14}$

$E=5.37\times 10^{-19}\ J$

So, the energy of one quantum of this radiation $5.37\times 10^{-19}\ J$. Hence, this is the required solution.