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bazaltina [42]
3 years ago
6

What is any motion in which an object is moving along a curved path

Physics
1 answer:
Usimov [2.4K]3 years ago
4 0
It's called "circular motion"


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Help ! Velocity............
Murrr4er [49]

Answer:

70.7m/s

Explanation:

V =     ( v + u)

          _____

               2

V = average velocity

v = final velocity

u = initial velocity

velocity = distance

                 ______

                   time

u (initial velocity)   = 33 ÷  2

change mins to seconds

1 min = 60 secs

2 mins =  ?

cross multiply

60 × 2 = 120 secs

u = 33 ÷ 120

u = 0.275m/s

v ( final velocity) = 29 ÷ 1.3

change mins to secs

1 min = 60 secs

1.3 mins = ?

cross multiply

1.3 × 60 = 78 secs

v = 29 ÷ 78

v = 0.371 m/s

V =  ( v + u )

       _____

           2

V =    ( 0.371 + 0.275)

         ____________

                    2

V  =   0.51 m/s

                           

5 0
3 years ago
Identify and draw the forces that act on the pencil. Be certain to draw each force at the correct location (the point at which t
Alekssandra [29.7K]

Answer:

Explanation:

find solution below

6 0
4 years ago
Calculate the average speed of a snake that moves 700 meters in 5 hours?
ddd [48]
140 ? i’m guessing there doesn’t look like there’s much to the question
7 0
4 years ago
Read 2 more answers
16g 2g/cm3 what is the Volume
lord [1]

Answer:

V =  1.25E-7 cubic meter

7 0
3 years ago
A toy car having mass m = 1.50 kg collides inelastically with a toy train of mass M = 3.60 kg. Before the collision, the toy tra
baherus [9]

Answer:

  v_{f} = 3,126 m / s

Explanation:

In a crash exercise the moment is conserved, for this a system formed by all the bodies before and after the crash is defined, so that the forces involved have been internalized.

the car has a mass of m = 1.50 kg a speed of v1 = 4.758 m / s and the mass of the train is M = 3.60 kg and its speed v2 = 2.45 m / s

Before the crash

    p₀ = m v₁₀ + M v₂₀

After the inelastic shock

    p_{f}= m v_{1f} + M v_{2f}

    p₀ =  p_{f}

    m v₀ + M v₂₀ = m v_{1f}  + M v_{2f}

We cleared the end of the train

     M v_{2f} = m (v₁₀ - v1f) + M v₂₀

Let's calculate

     3.60 v2f = 1.50 (2.15-4.75) + 3.60 2.45

     v_{2f}  = (-3.9 + 8.82) /3.60

      v_{2f}  = 1.36 m / s

As we can see, this speed is lower than the speed of the car, so the two bodies are joined

set speed must be

      m v₁₀ + M v₂₀ = (m + M) v_{f}

      v_{f}  = (m v₁₀ + M v₂₀) / (m + M)

      v_{f}  = (1.50 4.75 + 3.60 2.45) /(1.50 + 3.60)

      v_{f} = 3,126 m / s

4 0
4 years ago
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