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bekas [8.4K]
2 years ago
12

What characteristics of a planet determine the strength of its gravitational force on other objects? A. diameter of the planet a

nd its location in space B. mass of the planet and its distance from other objects C. the distance of the planet from the Earth D. the number of moons that the planet has
Physics
1 answer:
Vanyuwa [196]2 years ago
6 0

Answer:

mass of the planet and its distance from other objects

Explanation:

mass of the planet and its distance from other objects determine the strength of its gravitational force on other objects

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A bowling (mass = 7.2 kg, radius = 0.11 m) and a billiard ball (mass = 0.38 kg, radius = 0.028 m) may each be treated as uniform
cestrela7 [59]
Hope this helps you!

7 0
2 years ago
If the velocity of a pitched ball has a magnitude of 44.5 m/sm/s and the batted ball's velocity is 55.5 m/sm/s in the opposite d
Yuliya22 [10]

Incomplete question as the mass of baseball is missing.I have assume 0.2kg mass of baseball.So complete question is:

A baseball has mass 0.2 kg.If the velocity of a pitched ball has a magnitude of 44.5 m/sm/s and the batted ball's velocity is 55.5 m/sm/s in the opposite direction, find the magnitude of the change in momentum of the ball and of the impulse applied to it by the bat.

Answer:

ΔP=20 kg.m/s

Explanation:

Given data

Mass m=0.2 kg

Initial speed Vi=-44.5m/s

Final speed Vf=55.5 m/s

Required

Change in momentum ΔP

Solution

First we take the batted balls velocity as the final velocity and its direction is the positive direction and we take the pitched balls velocity as the initial velocity and so its direction will be negative direction.So we have:

v_{i}=-44.5m/s\\v_{f}=55.5m/s

Now we need to find the initial momentum

So

P_{1}=m*v_{i}

Substitute the given values

P_{1}=(0.2kg)(-44.5m/s)\\P_{1}=-8.9kg.m/s

Now for final momentum

P_{2}=mv_{f}\\P_{2}=(0.2kg)(55.5m/s)\\P_{2}=11.1kg.m/s

So the change in momentum is given as:

ΔP=P₂-P₁

=[(11.1kg.m/s)-(-8.9kg.m/s)]\\=20kg.m/s

ΔP=20 kg.m/s

3 0
3 years ago
(2.437×10⁴)(6.5411 x 10^9)/(5.37x10^6). write in scientific notation​
Musya8 [376]

Answer:

the answee is

2.968456 ×10^7

4 0
3 years ago
A crate is being lifted into a truck. If it is moved with a 2470 N force and 4850 J of work is done, then how far is the crate b
olchik [2.2K]

Answer:1.96m

Explanation:

Work=4850J

Force=2470N

Distance =work ➗ force

Distance =4850 ➗ 2470

Distance =1.96m

7 0
3 years ago
A force of 100 newtons was necessary to lift a rock. a total of 150 joules of work was done. how far was the rock lifted
Makovka662 [10]

Answer:

1.5m

Explanation:

150÷100=1.5

Work done ÷force

4 0
3 years ago
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