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bekas [8.4K]
3 years ago
12

What characteristics of a planet determine the strength of its gravitational force on other objects? A. diameter of the planet a

nd its location in space B. mass of the planet and its distance from other objects C. the distance of the planet from the Earth D. the number of moons that the planet has
Physics
1 answer:
Vanyuwa [196]3 years ago
6 0

Answer:

mass of the planet and its distance from other objects

Explanation:

mass of the planet and its distance from other objects determine the strength of its gravitational force on other objects

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anyanavicka [17]
The Answer: Parallel
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3 years ago
Read 2 more answers
A transport plane takes off from a level landing field with two gliders in tow, one behind the other. The mass of each glider is
velikii [3]

Answer:

(a)  Length =136.58 m

(b)  T=5995 N

Explanation:

for the glider in the back

T - 1900 = 700 a

for the glider in front

12000-T -1900 = 700a

add equations

12000-3800 = 1400 a

a=5.85 m/s^2

v^2 = v0^2 + 2 a x

40^2 = 2*5.85*x

Length =136.58 m

b) plug the a back into one of the previous formula

T -  1900 = 700*5.85

T=5995 N

8 0
3 years ago
3. What will happen to the black bass and blue gill as the floor of the ponds fills with organic
yKpoI14uk [10]

Answer: die

Explanation: oyxagan all goon bc of all dat suffs

8 0
3 years ago
24. An elevator is moving vertically up with an acceleration a. The force exerted on the floor by a passenger of mass m is
Wewaii [24]

<u>Given </u><u>:</u><u>-</u>

  • An elevator is moving vertically up with an acceleration a.

<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>

  • The force exerted on the floor by a passenger of mass m .

<u>Solution</u><u> </u><u>:</u><u>-</u>

As the man is in a accelerated frame that is <u>non </u><u>inertial</u><u> frame</u><u> </u>, we would have to think of a pseudo force .

  • The direction of this force is opposite to the direction of acceleration the frame and its magnitude is equal to the product of mass of the concerned body with the acceleration of the frame .

For the FBD refer to the attachment . From that ,

\implies Weight_{apparent}= mg + ma

<u>Hence</u><u> </u><u>option</u><u> </u><u>d </u><u>is </u><u>correct</u><u> </u><u>choice </u><u>.</u>

<em>I </em><em>hope</em><em> this</em><em> helps</em><em> </em><em>.</em>

3 0
2 years ago
A sailor strikes the side of his ship just below the waterline. He hears the echo of the sound reflected from the ocean floor di
Marrrta [24]

Answer:

2625 m deep

Explanation:

Let the sound speed in sea water be 1500 m/s. If he hears the echo 3.5s after the strike, then the sound would have traveled a distance of 1500 * 3.5 = 5250 m to the bottom and back. This would mean the ocean is 5250 / 2 = 2625 m deep.

5 0
3 years ago
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