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Fittoniya [83]
3 years ago
11

Balance the following half-reaction: (acidic) NO−3(aq) → NO2(aq) Express your answer as a half-reaction. Identify all of the pha

ses in your answer.
Chemistry
1 answer:
Marrrta [24]3 years ago
8 0

Answer:

2H⁺  + NO₃⁻  + 1e⁻ →  NO₂  + H₂O

Explanation:

NO₃⁻  →  NO₂

In left side, Nitrogen acts with +5 by oxidation number

In right side, the oxidation number is +4

This is a reduction reaction, because the oxidation number has decreased. So the N has gained electrons.

NO₃⁻  + 1e⁻ →  NO₂

In acidic medium, we have to add water, where there are less oxygens to ballance the amount. We have 2 O in left side, and 3 O in right side, so we have to add 1 H₂O on left side.

NO₃⁻  + 1e⁻ →  NO₂  + H₂O

Now that oxygens are ballanced, we have to ballance the hydrogens by adding protons in the opposite side

2H⁺  + NO₃⁻  + 1e⁻ →  NO₂  + H₂O

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Which statement explains the relationship between the amount of energy it takes to break a bond and the amount of energy release
ad-work [718]

<em>The statement that gives the relationship between energy needed in breaking a bond and the one that is released after breakin</em>g is

The amount of energy it takes to break a bond is always less than the amount of energy released when the bond is formed.

  • Bond energy can be regarded as amount of energy that is required in  breaking a particular bond.

  • For a bond to be broken Energy will be  added and when a bond is broken there will be release of energy

  • Bond breaking can be regarded as endothermic process, it is regarded as endothermic  because there is a lot of energy required to be absorbed.

  • Where ever a bond is broken, there must be formation of another bond

  • Bond forming on the other hand can be regarded as exothermic process, since there is a release of  releases energy.

Therefore, more energy is required in breaking of bond compare to energy released after breaking of bond.

Learn more at : brainly.com/question/10777799?referrer=searchResults

6 0
3 years ago
How to balance the equation Mg2+HO2=Cu3O+H2<br><br>​
Mariulka [41]
I think the answer is 2Mg + H2O4 = Cu12O4 + 2H

I’m really not sure though so it might be wrong… I’m not the best at balancing equations lol
6 0
2 years ago
What is the chemical composition of the mobile phase in this experiment?
Alecsey [184]
H2SO.Mgslfurmobile phase in this experiment
6 0
3 years ago
A chemical plant produces ammonia using the following reaction at a very high temperature and pressure. Which design issue is mo
Lorico [155]

Answer:

D. The equipment needed to accommodate the high temperature and pressure will be expensive to produce.​

Explanation:

Hello!

In this case, for the considered reaction, it is clear it is an exothermic reaction because it produces energy; and therefore, the higher the temperature the more reactants are yielded as the reverse reaction is favored. Moreover, since the effect of pressure is verified as favoring the side with fewer moles; in this case the products side (2 moles of ammonia).

In such a way, the high pressure favors the formation of ammonia whereas the high temperature the formation of hydrogen and nitrogen and therefore, option A is ruled out. Since the high pressure shifts the reaction rightwards and the high temperature leftwards, we would not be able to know whether the reaction has ended or not because it will be a "go and come back" process, that is why B is also discarded. Now, since hydrogen and nitrogen would be the "wastes", we discard C because they are not toxic. That is why the most accurate answer would be D. because it is actually true that such equipment is quite expensive.

Best regards!

6 0
3 years ago
Calculate the de Broglie wavelength of a body of mass 1 kg moving with a velocity of
skelet666 [1.2K]

Answer:

4.42 × 10⁻³⁷ m

Explanation:

Step 1: Given and required data

  • Mass of the body (m): 1 kg
  • Velocity of the body (v): 1500 m/s
  • Planck's constant (h): 6.63 × 10⁻³⁴ J.s

Step 2: Calculate the de Broglie wavelenght (λ) of the body

We will use de Broglie's equation.

λ = h / m × v

λ = (6.63 × 10⁻³⁴ J.s) / 1 kg × (1500 m/s) = 4.42 × 10⁻³⁷ m

6 0
3 years ago
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