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VLD [36.1K]
3 years ago
5

How long would it take Jesse with an acceleration of -2.50 m/s^2 to bring his bicycle with an initial velocity of 13.5 m/s to a

complete stop?
a.6.1 s
b.3.7 s
c.12.1 s
D.5.4 s
Physics
2 answers:
Vanyuwa [196]3 years ago
8 0

Explanation:

u = 13.5 m/s

a = - 2.5 m/s^2

<u>v = u + at</u>

0 = 13.5 - 2.5 * t

<u>t</u><u> </u><u>(</u><u>time</u><u> </u><u>to</u><u> </u><u>reach</u><u> </u><u>a</u><u> </u><u>complete</u><u> </u><u>halt</u><u>)</u><u> </u><u>=</u><u> </u> <u>5.4 sec</u>

zhannawk [14.2K]3 years ago
7 0

Answer:

use first equation of motion v=u+at..v is 0..since we have to take him to rest and u is 13.5

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Answer:

4.06 Hz

Explanation:

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3 years ago
Find the resistance of wire of<br>0.65m Radius 0.25<br>and<br>resistivity 3x10-6 OHM<br>​
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Complete Question:

Find the resistance of a wire of length 0.65 m, radius 0.25 mm and resistivity 3 * 10^{-6} ohm-metre.

Answer:

Resistance = 9.95 Ohms

Explanation:

<u>Given the following data;</u>

Length = 0.65 m

Radius = 0.25 mm to meters = 0.00025 m

Resistivity = 3 * 10^{-6} ohm-metre.

To find the resistance of the wire;

Mathematically, resistance is given by the formula;

Resistance = P \frac {L}{A}

Where;

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First of all, we would find the cross-sectional area of the wire.

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Substituting into the equation, we have;

Area  = 3.142 * (0.00025)²

Area = 3.142 * 6.25 * 10^{-8}

Area = 1.96 * 10^{-7} m²

Now, to find the resistance of the wire;

Resistance = 3 * 10^{-6} * \frac {0.65}{1.96 * 10^{-7}}

Resistance = 3 * 10^{-6} * 3316326.531

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On the scale model, this would corresponds to a distance of x_2.

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And solving for x_2, we find:

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Answer:

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