The refrigerator's coefficient of performance is 6.
The heat extracted from the cold reservoir Q cold (i.e., inside a refrigerator) divided by the work W required to remove the heat is known as the coefficient of performance, or COP, of a refrigerator (i.e., the work done by the compressor). The required inside temperature and the outside temperature have a significant impact on the COP.
As the inside temperature of the refrigerator decreases, its coefficient of performance decreases. The coefficient of performance (COP) of refrigeration is always more than 1.
The heat produced in the cold compartment, H = 780.0 J
Work done in ideal refrigerator, W = 130.0 J
Refrigerator's coefficient of performance = H/W
= 780/130
= 6
Therefore, the refrigerator's coefficient of performance is 6.
Energy conservation requires the exhaust heat to be = 780 + 130
= 910 J
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Answer:
C. 32.7%
Explanation:
% composition = ( mass S / mass H2SO4 ) × 100 = 32.08/ 98.10 × 100 = 32.7 % pls mark brainliest
Answer:
The term rotational and irrotational flow is associated withe the flow of particles in fluid.
The common example of irrrotational flow can be seen on the carriages of the Ferris wheel (giant wheel).
Explanation:
- If the fluid is rotating along its axis with the streamline flow of its particles,then this type of flow is rotational flow.
- Similarly if fluid particles do not rotate along its axis while flowing in a stream line flow then it is considered as the irrotational flow.
- In majority, if the flow of fluid is viscid then it is rotational.
- Fluid in a rotating cylinder is an example of rotating flow.
I think metal, steel and copper.
Answer: C
Explanation: Air
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