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gogolik [260]
3 years ago
5

A student throws a heavy red ball horizontally from a balcony of a tall building with an initial speed v0. At the same time, a s

econd student drops a lighter blue ball from the same balcony. Neglecting air resistance, which statement is true?
(A) The blue ball reaches the ground first.
(B) The balls reach the ground at the same instant.
(C) The red ball reaches the ground first.
(D) Both balls hit the ground with the same speed. (E) None of the above statements is true.
Physics
1 answer:
MAVERICK [17]3 years ago
5 0

Answer:

(B) The balls reach the ground at the same instant.

Explanation:

Since it is a projectile motion, the time required to reach the ground is given by

t = √2h/g

Where h is the height from which the balls are thrown and g is the acceleration due to gravity.

Since both of the balls were thrown from the same height and the acceleration of both balls are also same they will reach the ground at the same instant.

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When did they start using the word "Scrubbed" for launches?
VladimirAG [237]

Answer:

Many speculation exists for why the term 'scrubbed' is used in relation to launches. <em>One of these is that during world war II, when the Air force planned bombing raids</em>. These  Air force missions had their briefings done with illustration of the details of the launch and and flight drawn on chalkboards. <em>When some of mission flight takeoffs were canceled (due to bad weather or a malfunction or other reasons) the details were then scrubbed off of the chalkboard</em>. This idea of the mission <em>being scrubbed meaning that it is no longer to be followed through with</em>, proceeded to this modern day rocket and aviation launches.

6 0
4 years ago
Two identical automobiles are
Phantasy [73]

Answer:

i think that it is b but I could be wrong

3 0
3 years ago
Name 8 examples of Convection.
REY [17]
1: Boiling Water
2: Ice Melting
3: Hot Air Balloon 
4: Frozen Material Thawing
5: Radiator
6: Steaming cup of hot coffee
7: Campfire
8: Putting wet shoes on floor vent
5 0
3 years ago
A 45.0 kg student runs at a constant velocity up the incline 6 metres high. If the power output of the student is 1.50 x 103 W,
serg [7]

Answer:

The time taken is 1.76 s.

Explanation:

mass of student, m = 45 kg

height, h = 6 m

power, P = 1500 W

Power is defined as the rate of doing work.

Work done in moving height is

W = m g h

Let the time is t.

P = m g h / t

1500 = 45 x 9.8 x 6 / t

t = 1.76 s

3 0
3 years ago
A space rocket is launched and accelerates uniformly to 160 m/s in 4.5 s. Calculate the acceleration of the rocket.​
-BARSIC- [3]

Answer:

<h2>35.56 m/s²</h2>

Explanation:

The acceleration of an object given it's velocity and time taken can be found by using the formula

a =  \frac{v}{t}  \\

v is the velocity

t is the time

From the question we have

a =  \frac{160}{4.5}  = 35.55555...

We have the final answer as

<h3>35.56 m/s²</h3>

Hope this helps you

6 0
3 years ago
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