Answer:
29.41% of Calcium and 47.04% of Oxygen
Explanation:
The percent composition of an atom in a molecule is defined as 100 times the ratio between the mass of the atom and the mass of the molecule.
The mass of the molecule of the problem (Ore) is 46.28g. That means the percent composition of Calcium is:
13.61g / 46.28g * 100 = 29.41% of Calcium
And percent composition of Oxygen is:
21.77g / 46.28g * 100 = 47.04% of Oxygen
The nucleus of an atom contain neutrons and protons, and energy levels surround the nucleus, in rings and contain electrons
The percentage yield of the new production technique is 82.8%
<h3>What is the percentage yield?</h3>
Production is the procedure by which finished products are obtained form the raw materials. The production process involves the passing of raw materials through a certain procedure that involves the use of certain machines and equipment to give us the required products.
We are told in the question that there are three shifts;
Shift 1 produces 4562 grams
Shift 2 produces 5783 grams
Shift 3 produces 5247 grams
Average production from the three shifts = 4562 grams + 5783 grams + 5247 grams/3 = 5197 grams
The theoretical average yield is = 7000 grams + 7000 grams + 7000 grams/3 = 7000 grams
Now the percentage yield = actual yield/ theoretical yield * 100/1
percentage yield = 5197 grams/7000 grams * 100/1
percentage yield = 82.8%
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The volume (in cm³) gained by a person who gains 11.8 lb of fat is 5830.49 cm³
<h3>What is density? </h3>
The density of a substance is simply defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as
Density = mass / volume
<h3>How to convert pounds to grams </h3>
1 lb = 453.592 g
Therefore,
11.8 lb = 11.8 × 453.592
11.8 lb = 5352.3856 g
<h3>How to determine the volume </h3>
- Mass = 5352.3856 g
- Density = 0.918 g/cm³
- Volume =?
Volume = mass / density
Volume = 5352.3856 / 0.918
Volume = 5830.49 cm³
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Answer:
C.0.28 V
Explanation:
Using the standard cell potential we can find the standard cell potential for a voltaic cell as follows:
The most positive potential is the potential that will be more easily reduced. The other reaction will be the oxidized one. That means for the reactions:
Cu²⁺ + 2e⁻ → Cu E° = 0.52V
Ag⁺ + 1e⁻ → Ag E° = 0.80V
As the Cu will be oxidized:
Cu → Cu²⁺ + 2e⁻
The cell potential is:
E°Cell = E°cathode(reduced) - E°cathode(oxidized)
E°cell = 0.80V - (0.52V)
E°cell = 1.32V
Right answer is:
<h3>C.0.28 V
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