Write balanced molecular, ionic, and net ionic equations<span> (NIE) for each of the ... </span>3.Mg(OH)2(aq) +. 2HCl(aq). →. MgCl2(aq). +. 2H2O(l). Ionic Equation: Mg2+(aq). + ... 2-(aq). +. Ca2+(aq). →. Ca(C2O4)(s). 5. 2(NH4)3PO4(aq) +. 3Zn(NO3)2(aq) → ... 2-(aq<span>). →. MgCrO4(s). 9. </span>2FeCl3(aq<span>). +. </span>3Mg<span>(s). →. </span>3MgCl2(aq<span>) +. </span>2Fe<span>(s).</span>
I think the correct word to fill in the blank would be carbon. Organic compounds are composed of carbon and at least one hydrogen atom. It is basically any compound that would contain carbon and covalently bonded to other elements or atoms usually these are hydrogen, nitrogen and oxygen. All living things are based on these compounds. These are the building blocks of organic chemistry. These compounds can be seen anywhere in Earth. May it be animals, plants, the soil, sugar, microorganisms and even in humans. Examples of these compounds are methanol, DNA, glucose, hexane, acetic acid, butane and the like.
Answer:
In the mid-nineteenth century, the actual mechanism for evolution was independently conceived of and described by two naturalists: Charles Darwin and Alfred Russel Wallace. Importantly, each naturalist spent time exploring the natural world on expeditions to the tropics. From 1831 to 1836, Darwin traveled around the world on H.M.S. Beagle, including stops in South America, Australia, and the southern tip of Africa. Wallace traveled to Brazil to collect insects in the Amazon rainforest from 1848 to 1852 and to the Malay Archipelago from 1854 to 1862. Darwin’s journey, like Wallace’s later journeys to the Malay Archipelago, included stops at several island chains, the last being the Galápagos Islands west of Ecuador. On these islands, Darwin observed species of organisms on different islands that were clearly similar, yet had distinct differences. For example, the ground finches inhabiting the Galápagos Islands comprised several species with a unique beak shape
Answer:
Percentage of first isotope = 69.152 %
Percentage of second isotope = 30.848 %
Explanation:
The formula for the calculation of the average atomic mass is:
Given that:
For first isotope:
Let % = x %
Mass = 62.9296 amu
For second isotope:
% = 100 - x % (Since, there are only two isotopes)
Mass = 64.9278 amu
Average mass = 63.546 amu
Thus,
Solving,
1.9982 x = 138.18
Thus,
<u>Percentage of first isotope = x = 69.152 %</u>
<u>Percentage of second isotope = 100 - x % = 30.848 %</u>
