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MakcuM [25]
3 years ago
6

How many moles of (NH4)2S are there in 150 g of (NH4)2S?

Chemistry
1 answer:
NikAS [45]3 years ago
8 0
The answer
the number of moles can be found easily by using formula of molar mass

Molar mass = mass (g)  / number of moles (mol)

from this, we can get number of
 
number of moles (mol) =mass (g)  / Molar mass

the mass molar of <span>(NH4)2S :
M(</span><span>(NH4)2S) = (14+ 4x1) x 2  + 32 = 36+32 = 48 g/ mol
</span>
number of moles (mol) = <span>150 g / 48 = 3.12 moles</span>
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Answer: A.) Removing a few marbles from the petri dish and stirring the rest around as energy is added

B) The high temperature makes the gas molecules spread apart according to Charles's law because this law describes how a gas will behave at constant pressure.

Explanation: The phase transition from solid to liquid involves the use of energy to make the molecules present in solid to break the inter molecular forces and to start moving away from each other as in liquid. The molecules in solid are closely packed whereas in liquids they are loosely packed. Thus less number of molecules are present per unit volume in a liquid. Thus the marbles have to be removed to show less density and the energy has to supplied. Removing all but two marbles from the petri dish and shaking them vigorously as energy is added will give us a more disorderd state called gas in which the molecules are very far apart and the density is least.

B) According to Boyle's law the pressure is inversely proportional to the volume of the gas at constant temperature and constant number of moles. P\propto \frac{1}{V}     (At constant temperature and number of moles)

According to Charle's law the volume is directly proportional to the temperature of the gas at constant pressure and constant number of moles.

V\propto T    (At constant pressure and number of moles)

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2 years ago
A student dissolves of glucose in of a solvent with a density of . The student notices that the volume of the solvent does not c
nikitadnepr [17]

Answer:

0.052 M

0.059 m

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There is some missing info. I think this is the complete question.

<em>A student dissolves 4.6 g of glucose in 500 mL of a solvent with a density of 0.87 g/mL. The student notices that the volume of the solvent does not change when the glucose dissolves in it. Calculate the molarity and molality of the student's solution. Round both of your answers to 2 significant digits.</em>

Step 1: Calculate the moles of glucose (solute)

The molar mass of glucose is 180.16 g/mol.

4.6 g × 1 mol/180.16 g = 0.026 mol

Step 2: Calculate the molarity of the solution

0.026 moles of glucose are dissolved in 500 mL (0.500 L) of solution. We will use the definition of molarity.

M = moles of solute / liters of solution

M = 0.026 mol / 0.500 L = 0.052 M

Step 3: Calculate the mass corresponding to 500 mL of the solvent

The solvent has a density of 0.87 g/mL.

500 mL × 0.87 g/mL = 435 g = 0.44 kg

Step 4: Calculate the molality of the solution

We will use the definition of molality.

m = moles of solute / kilograms of solvent

m = 0.026 mol / 0.44 kg = 0.059 m

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